39. ★★ A copper loop in the shape of an equilateral tri-angle ABC (AB = AC = BC = a), carrying an electriccurrent, I, is placed in a uniform magnetic field ofmagnitude B directed parallel to side AC of the tri-angle (Figure 24-66).(a)Find the magnitude of the magnetic force exertedon each side of the triangle.(b) Find the net magnetic force exerted on this triangleby the magnetic field.(c)Find the magnetic torque exerted on this triangleby this magnetic field.YKTraBBс

The copper triangle ABC is placed in a uniform magnetic field B→ that is parallel to side AC of the…

39. ★★ A copper loop in the shape of an equilateral tri- angle ABC (AB=AC = BC = a), carrying an electric current, I, is placed in a uniform magnetic field of magnitude B directed parallel to side AC of the tri- angle (Figure 24-66). (a) (b) (c) Find the magnitude of the magnetic force exerted on each side of the triangle. Find the net magnetic force exerted on this triangle by the magnetic field. Find the magnetic torque exerted on this triangle by this magnetic field. B B

39. ★★ A copper loop in the shape of an equilateral tri- angle ABC (AB=AC = BC = a), carrying an electric current, I, is placed in a uniform magnetic field of magnitude B directed parallel to side AC of the tri- angle (Figure 24-66). (a) (b) (c) Find the magnitude of the magnetic force exerted on each side of the triangle. Find the net magnetic force exerted on this triangle by the magnetic field. Find the magnetic torque exerted on this triangle by this magnetic field. B B

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

A proton moves perpendicular to a uniform magnetic field B at a speed of 2.10 x 10' m/s and experiences an acceleration of 1.90 x 1013 m/s in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field. magnitude direction ---Select--- v
A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x 10’ m/s and experiences an acceleration of 1.60 × 1013 m/s in the positive x direction when its velocity is in the positive z direction. Determine the magnitude and direction of the field. magnitude direction |---Select--- ♥V
A proton moving in the positive x direction with a speed of 8.2 x 105 m/s experiences zero magnetic force. When it moves in the positive y direction it experiences a force of 1.6 x 10-13 N that points in the positive z direction. Determine the magnitude and direction of the magnetic field. magnitude direction |---Select- v -Select--- Additional M: O Reading -z
A nonconducting ring of radius is uniformly charged with a total positive charge R. 9- The ring rotates at a constant angular speed about an axis through its center, perpendicular to the plane of the ring. What is the magnitude of the magnetic fieldi O A) 47R B) 4R O0 4R O PL ZTR
6) A charged particle has velocity Jo = vfê + všŷ when it enters a region of uniform magnetic field B = Bââ, setting the particle on a helical motion. a) Determine the radius of the helix. b) Determine the time it takes to complete one full turn of the helix. c) Determine the displacement in the r-direction during the the time to complete one full turn of the helix.
Magnetic field
The direction of the force on a current carrying wire located in an external magnetic field is which I O perpendicular to the current O perpendicular to the field O Both choices A and B are valid. None of the above are valid.
These two long parallel wires each carry current /= 13 A in opposite directions. A B 2 om 2 cm 2cm 2 m Determine the magnitude of the net magnetic field (in uT) at point C. A Moving to another question will save this resporsE.
SS1) Try to solve the Sub-part (a) only.Give me a correct solution.
A charged particle, after entering a constant magnetic field B, starts moving freely along a circular path in the magnetic field applied perpendicular to the particle’s velocity (v). What do you conclude about the particle’s kinetic energy (KE)? Group of answer choices KE remains unaltered as v and FB are perpendicular to each other KE increases under the constant magnetic force FB. KE decreases when magnetic force (FB) is perpendicular to the motion (v). KE and magnetic force FB are not correlated.
A wire of mass 10 grams and length 50 cm carries a Southward current of 2A while resting on a horizontal table on Earth. a) If a vertically downward uniform magnetic field of 0.2 T is applied, determine the direction and magnitude of the magnetic force on the wire. b) Determine the acceleration of the wire if its coefficient of kinetic friction with the table is 0.4. c) Determine the direction and magnitude of the smallest uniform magnetic field required to levitate the wire.