6) A charged particle has velocity Jo = vfê + včý when it enters a region of uniform magnetic field B = Bâ, setting the particle on a helical motion. a) Determine the radius of the helix. b) Determine the time it takes to complete one full turn of the helix. c) Determine the displacement in the r-direction during the the time to complete one full turn of the helix.
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- 4. A negatively charged particle (q -22.0μC) travels at a constant speed of 3.20 x 10 m/s out of this page. It then enters a uniform magnetic field of magnitude 3.75 × 105 T that points towards the top of this page. a) What is the maximum magnitude of the magnetic force?A wire with a current of 6.4 A is in a uniform magnetic field B - Bai + By] + B,k Where B= =8.9T. and By =45T, and Be =44.8T are the components of the magnetic field. The wire is oriented along the x-axis and is carrying the current in the +x direction and has a length 7.76m What is the magnitude of the magnetic force on the wire (in INy? I need to show all worka) what is the magnitude of the magnetic field produced at origin ? b) what is the magnitude of magnetic force that q` exerted on q?
- 1) The total magnetic field to any current carrying conductor can be solved by a integration b laplacian c curl d differentiation 2) A charge is accelerated from rest through a potential difference. Which of the following is true? a The velocity of the charge is directly proportional to the magnitude of the potential difference b The acceleration of the charge is directly proportional to the square root of the magnitude of the potential difference. c The acceleration of the charge is directly proportional to the magnitude of the potential difference d The answer cannot be found on the other choices 3) Electric fields can be sources of magnetic fields. When does this happen? a. When the electric field is static and the charge in the said electric field is moving with uniform velocity b. When the electric field is static c. The answer cannot be found on the other choices. d. When the electric field is static and the charge in the said electric field is moving with constant…MOI The strength of the magnetic field B at a distance r from a straight conductor carrying a current I is given by the expression B = 2лr where μo is the permeability of free space with the value 4 x 10-7 NA-2. Two long straight wires are lined up parallel to one another at a separation of 0.17 m. Currents of 4 A and 2 A flow through the wires, both in the same direction. Calculate the absolute value of the magnetic field strength due to the two wires at a point P on the mid-plane between them. Give your answer in micro Tesla (µT, 10-6).15. A 52uC charge particle moves parallel to a long wire with a speed of 720 m/s. The separation between the particle and the wire is 13 cm, and the magnitude of the force exerted on the particle is 1.4 x 10-7. Find the magnitude of the magnetic field at that point, and the current in the wire.
- Consider the current-carrying wire shown in the figure. The current creates a magnetic field at the point P, which is the center of the arc segment of the wire. If 0 = 30.0°, the radius of the arc is 0.800 m, and the current is 5.00 A, what are the magnitude (in nT) and direction of the field produced at P? magnitude 3.272*10**-7X Did you forget to convert from T to nT? nTThe vector velocity will always be to the right and the magnetic field will be into the screen or out of the screen. The angle is 90 degrees. Determine the magnitude of the magnetic force and the radius of the curvature. Will the charge be deflected to the left, or to the right or not at all when it enters the magnetic field? Strength of magnetic Field (B): 6.0T Mass of charge (m): 5.0x10-25 kg Charge (q): 4.0 x 10-16 C Velocity (v): 5.0 x 106 m/sA particle of mass m carrying a negative charge q passes through a perpendicular magnetic field B al speed v. as shown below. The radius of its circular path while it is within the magnetic field is r. (see diagram) Which of the following is equal to the speed, r. of the particle? A) qr/mB B) qBr/m C) qB/rm D) m/qBr