37% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The randomvariable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. Complete parts (a) through (c) below.(a) Construct a binomial distribution using n = 6 and p = 0.37.P(x)X0123456(Round to the nearest thousandth as needed.)

Binomial probability pmf has used.

Answered: 37% of working mothers do not have…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Using the Table and the data found in part c please answer the question in part e.
K Determine whether the given procedure results in a binomial distribution. If not, state the reason why. Rolling a single die 53 times, keeping track of the "fives" rolled. OA. Not binomial: the trials are not independent. B. The procedure results in a binomial distribution. OC. Not binomial: there are more than two outcomes for each trial. OD. Not binomial: there are too many trials.
A bag has 5 apples, 10 oranges, and 5 peaches. What is the probability of pulling out an apple? Enter your answers in this order: reduced fraction, decimal, and then percent. ?(?)=P(A)= Answer (reduced fraction) == Answer (decimal) == Answer%% This is an example of Answer probability. The sample space is ?={S={Answer }}(Enter your answer in alphabetical order with a comma and no spaces.) In this case, the "event" is what? Answer. What is the probability of pulling out an orange? ?(?)=P(O)= Answer (reduced fraction) == Answer (decimal) == Answer%%. Which is more likely to occur? Answer Why? Answer
Assume that the normal distribution can be used to approximate the following binomial distribution question. A survey of adults found that 6% say their favorite sport is auto racing. You randomly select 400 adults and ask them to name their favorite sport. Complete parts (a) and (b). (a) Find the probability that the number of people who say auto racing is their favorite sport is at most 30. (b) Find the probability that the number of people who say auto racing is their favorite sport is more than 33. (Round to four decimal places as needed.)
A deck of four (4) cards has exactly one (1) color printed on each face – blue, yellow, red, or green. You have two (2) identical decks of this type. In this game, you randomly select a card from each of the two decks. Your score is the number of blue cards drawn – refer to this quantity as X. The probability distribution is below: X P(X) 0 0.5625 1 0.375 2 0.0625 What is the average number of blue cards drawn? What is the probability that at most one blue card is drawn?
please solve 4 a, b and c
The random variable x represents the number of cars per household in a town of 1000 households. Find the probability of randomly selecting a household that has between one and three cars, inclusive. Cars Households 0 135 1 418 2 242 3 122 4 83 0.218 0.782 0.135 0.418
You are bidding on six items available on an online shopping site. You think that for each bid you have a 35% chance of winning it, and the outcomes of the six bids are independent events. Let X denote the number of winning bids out of the six items you bid on. Find the probabilities. a. Explain why the distribution of X can be modeled by the binomial distribution. b. Find the probability that you win exactly 4 bids. c. Find the probability that you win 4 bids or fewer. d. Find the probability that you win more than 4 bids. a. Explain why the distribution of X can be modeled by the binomial distribution. A. The trials are independent. O B. The data are binary. C. The data are not binary. D. Probabilities of success for trials (bids) differ for each trial. OE. The trials are dependent. F. There is the same probability of success for each trial (bid). G. There are a fixed number of bids. O H. The number of bids varies. b. The probability of winning exactly 4 bids is (Round to four…
A deck of four (4) cards has exactly one (1) color printed on each face – blue, yellow, red, or green. You have two (2) identical decks of this type. In this game, you randomly select a card from each of the two decks. Your score is the number of blue cards drawn – refer to this quantity as X. The probability distribution is below: X P(X) 0 0.5625 1 0.375 2 0.0625 1. If we replaced the yellow card in the first deck with another blue card, what would be the probability of drawing two blue cards? 2. If we replaced the yellow card in the first deck with another blue card, what distribution would the variable X follow?

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