just d-g 3. Using the same calorimeter as in problem 2, a student mixed 180.0 mL of 2.50 M HNO3 with180.0 mL of 2.55 M KOH.a. Write the neutralization reaction occurring.HNO3 + KOHKNO3+ H2O1>b. What is the final volume of the solution? What is its concentration (of the salt produced)?nal VolIB0.OML + 180mL)360ML#ofmales=V XMof HNg= 180mb x 2.50M1000 m= 0.45mol#ofmolesof = 180mL1000 mYLofKOHx 2.55M=0.46 mol0.45mol XI000=1-25 (M360MLHoLonc =c. If the density of the resulting solution is 1.05 g/mL, what is the mass of the resulting.С.solution?mass= Density x Volume= 1.05g/mx 360m378gd. The specific heat of the resulting solution is 3.87 J/g•°C. If the temperature change wasmeasured to be 20.8°C, how many joules did the solution absorb?е.How many joules did the calorimeter absorb?f. Calculate the total number of joules released by the reaction.g.Calculate AH neutralization in kJ/mol.64 EXPERIMENT 2 EXPERIMENT 2: DETERMINING THE CHANGE IN ENTHALPY OF A REACTIONQUESTIONS1. Why is the concentration of the base used greater than the concentration of the acid?The conc of the base is greater thon the concentration of theacid in order to ensure thot all of the acid reacts2. In a similar experiment, a student mixed 200.0 mL of hot water with 200.0 mL of cool water. Thetemperature change for the hot water was 26.5°C and the temperature change for the cool waterwas 24.2°C.AT 26. 5°CH.AT= 24.2 C%3Da.Calculate the joules lost by the hot water.=m CSAT= 200.09= - 22175.2J= -22.175KJX 4.184 J/g°C x (-26.5°C)%3Db. Calculate the joules absorbed by the cool water.Q=mCs AT:200.09 x 4.1845lg °C x 24.2 °C= 20. 251 KJ%3DCalculate the joules absorbed by the calorimeter.%3D= 22.175 - 20.251=D1.924KJ%3Dd. Calculate the calorimeter constant.(1.924x103)79.5J/°C%3DATC(24.2C.

Heat absorbed by the solution = mass × temperature change × Specific heat capacity

= 378g d. The specific heat of the resulting solution is 3.87 J/g °C. If the temperature change was measured to be 20.8°C, how many joules did the solution absorb? e. How many joules did the calorimeter absorb? f. Calculate the total number of joules released by the reaction. g. Calculate AH neutralization in kJ/mol.

= 378g d. The specific heat of the resulting solution is 3.87 J/g °C. If the temperature change was measured to be 20.8°C, how many joules did the solution absorb? e. How many joules did the calorimeter absorb? f. Calculate the total number of joules released by the reaction. g. Calculate AH neutralization in kJ/mol.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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