37 30 onstruct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatments Error Total 236.00 2 12 14 19.66 36 p-value Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process. Calculate the value of the test statistic (to 2 decimals).

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Chapter1: Starting With Matlab
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To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow.
50°C
60°C
39
33
29
34
41
37
44
26
37
30
Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary).
Source of Variation Sum of Squares Degrees of Freedom Mean Square F
Treatments
2
236.00
12
Temperature
14
Error
Total
Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process.
Calculate the value of the test statistic (to 2 decimals).
19.66
70°C
28
33
33
The p-value is greater than 0.10
What is your conclusion?
Do not reject the assumption that the mean yields for the three temperatures are equal
35
36
p-value
Transcribed Image Text:To study the effect of temperature on yield in a chemical process, five batches were produced at each of three temperature levels. The results follow. 50°C 60°C 39 33 29 34 41 37 44 26 37 30 Construct an analysis of variance table (to 2 decimals but p-value to 4 decimals, if necessary). Source of Variation Sum of Squares Degrees of Freedom Mean Square F Treatments 2 236.00 12 Temperature 14 Error Total Use a 0.05 level of significance to test whether the temperature level has an effect on the mean yield of the process. Calculate the value of the test statistic (to 2 decimals). 19.66 70°C 28 33 33 The p-value is greater than 0.10 What is your conclusion? Do not reject the assumption that the mean yields for the three temperatures are equal 35 36 p-value
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