350 mm 1B 300 Go mm 240 mm 70 mm A 54-kg crate resets on the 27-kg pickup tailgate. Calculate the tension T (in N, round off to whole number) in each of the two restraining cables, one of which is shown. The centers of gravity are at G, and G2. The crate is located midway between the two cables.

Q: in 60 48 A rectangular steel block is 3 inches long in the x direction, 2 inches long in the y…

A:

Q: Determine the area of the moment diagram of the structure M O-ML OU2 OMI O ML/2

A:

Q: used in a transmission not restrained in directio N/mm?.

A:

Q: Calculate force necessary to keep the 5 kg block from sliding down a frictionless incline of 20…

A: Note:-  According to Bartleby guidelines In case of multiple different question we have to gave…

Q: Q2) ACED frame is pinned at C and support by two identical wires at A and B. The two wires have…

A: In this question, it is a framed structure having pinned joint. The pinned joint will have two…

Q: The frame given in the figure R = 0.25m radius at point E a frictionless reel are available. Support…

A:

Q: a) Calculate the reaction force In the beam subjected to loads in the figure, at point B.

A: Note:-“Since you have asked multiple questions, we will solve the first question for you. If you…

Q: The frame shown is subjected to lateral loads as shown. Supports S, T, U, V, W, Z are rigid…

A: In portal method, 1. Hinges are assumed at middle of each member. 2. frame is cut at different…

Q: 02) (25Marka): The load shown in Figure (2) is supported by the four stainless steel wires of…

A:

Q: Fill in the blanks A: B: Mass of plane: 22,000 kg Tension, T: 400 N Determine the reactions at A and…

A:

Q: A tape of 30 m weighing 0.90 kg has a cross-sectional area of 0.0485cm2. The tape measures 30.00 m.…

A: Given Data: The length of the tape is, L=30 m The weight of the steel tape is, W=0.90 kg The…

Q: A square plate 2 m on each side is supported by four steel tie rods 6-mm-diameter from an overhead…

A:

Q: Pb4 The crane weighs 8 tons with center of gravity at G and is held in place by the pin connection…

A: Given :

Q: The 40-kg homogeneous plate is suspended from three cables. Determine the tension in cables at A, B…

A:

Q: A 30-m tape weighs 12.5 g/m and has a cross-section of 0.022 cm?. It measures correctly when…

A:

Q: A moment of 791b-ft about O is required to loosen the nut. Determine the smallest magnitude of the…

A: Moment required= 79 lb-ft Lever-arm (length) = 19 inch = (19/12) ft We have to find out the smallest…

Q: Stability Classify each of the following systems as stable or unstable. If unstable, indicate which…

A: A structure can be stable if the reactions at the supports are not concurrent or not passing from a…

Q: Member AB (helical spring) and Member AC (axial rod) are carrying a weight at point A Member AB has…

A: Given : For member AB (helical spring) ; The radius of helical spring, R = 90 mm = 0.09 mNumber of…

Q: Ex-3. A tape of 30 m weighing 0.90 kg has a cross-sectional area of 0.0485cm². The tape measures…

A: When the tension applied to the measuring tape is different than the standardization pull,then a…

Q: Using this problem for 9-10. The casting has a mass of 3 Mg. Suspended in a vertical position und…

A: The mass of casting m= 3 Mg = 3000 kgThe upward velocity of casting, v= 200 mm/stime, t= 0.3s

Q: 4) While trying to change a tire, the driver shown below applies a force, P, of 25 Ibs at each end…

A:

Q: hinged joint at point F.

A: A treadle of section ABCDEF is given in the problems. The weight of the man is acting at the point…

Q: Example A04-04. Replace the force system acting on the post by a resultant force and couple moment…

A: We have to find out the the resultant force and moment at point O.

Q: Problem 1 Consider the set-up shown below. Calculate the resultant moment of force at point A.

A: Moment at point A can be calculated by multiplying magnitude of force and distance of line of action…

Q: The linkage below is made using two A992 steel rods, each having a circular cross section. 10klp.…

A: This question is related to Strength of Material. We calculate Diameter of Bar AB and BC using…

Q: Tst Tal Tbw E- 200 GPa E- 1200 GPa E- 70 GPa L-1 m L- 1.8 m L-1.6 m 150 mm 1250 mm 800 mm 200 mm…

A: Data given: Asked: Calculate how much larger the steel wire (Tst) diameter compared to the other…

Q: 3) The segmented shaft shown below is made up of two shafts. Shaft (1) is a solid shaft with a…

A: Given data - To find -

Q: F 10 in. 6 in. 8 in. 6 in. B

A:

Q: A double cover butt riveted joint is used to connect two flat plates of 200 mm width and 14 mm…

A: Given data- A double cover butt riveted joint- Two flat plates of 200 mm width, b=200 mm, Thickness…

Q: - alyA- 三加,三▼ T Normal 1 No Spac. Heading 1 Heading 2 Title Paragraph Styles In order to hold the…

A: Fy=Fsin30Fx=Fcos30

Q: 5.5 The 600-lb uniform log OGA–G being its center of gravity–is held in the position shown by the…

A: The unknowns can be counted if the free body diagram is drawn.

Q: Determine the tensions in cables AB, AC, and AD. 1.75 m 2.25 m C. 1.55 m 0.45 m B 2.3 AO 110 kg…

A:

Q: Two 10”-15.3 lb channels are welded together as shown in the figure. Determine the moment of Inertia…

A: Solution;

Q: The beam shown below is subjected to a varying distributed loading, a couple, and a concentrated…

A:

Q: A couple consists of two vertical forces of 60lb each thru the box as shown. One force acts up…

A: Given A couple acting on a box required : equivalent couple having a). horizontal forces acting…

Q: Problem 4: An 800 N-m couple is applied to the flywheel as shown. The coefficient of belt friction…

A:

Q: 2 ft 90 65 200 lb 100 lb 2. A beam AB is loaded as shown. The beam is pin-connected to the wall at…

A: To find tension in rope and reaction at pin A

Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.