35° 35° 1) The diagram above shows a variation of the Russel Traction Apparatus, which is used to apply traction to a broken femur. If a physical therapist specifies that the traction force along the leg is to be 35 N, then what weight w would need to be hung from the apparatus?
Q: 100 N 120 N 260 N 0.4 m B. 0.5 m A 0.3 m 0.2 m 0.2 m
A: Force is a vector quantity and it is added algebraically if all the forces are in parallel with each…
Q: by
A: The free-body diagram for the situation can be given as,
Q: | 30° D.ịm D.1 m -0.2 m -0.3 m
A: Solution: Calculate the angle which T makes with the vertical. sinθ=35θ=sin-10.6θ=36.87° Calculate…
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Q: A 32° 32°
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Q: A ఇం 20° 15 kg
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Q: PROBLEM: Determine the tension in each cord in the figure shown. 32° 45° 389 N 525N 62° 559
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A: F1 = 8.4 N F2 = 3.8 N θ1 = 62oθ2 = θ3θ1 and θ2 are complementary angles
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- A 2 m long massless rod supports a 12 N weight. The left end of each rod is held in place by a frictionless pin. In each case, a vertical force F is holding the rods and the weights at rest. Rank the magnitude of the vertical force F applied to the rods. Example A B If two cases are equal they can go in either order.For the 22.0 kg sphere shown in the figure below, find the normal forces from each surface. Assume that all the surfaces are frictionless. R=40.0 cm 49.0% 27.0° Nright = Number N Njeft Number NIn the figure below, what is the magnitude of the force of A on B? * MĄ = 4.0 kg 20 kg В тв 36 N > A
- The crate is being pulled. coefficient of friction between ramp and floor non-sliding=0.300 sliding=0.250 0.450 m VIZUA 50 kg 0.750 m 50° Calculate for the highest value of force that can be applied to the crate without causing it to tip over?Select all that are True. Pulleys cannot be used to redirect tension forces. Pulleys can be arranged to amplify a tension force, to make lifting objects easier. Pulleys can be used to redirect tension forces. Pulleys cannot "give you something for nothing", so they cannot be used to amplify forces to make lifing objects easier. The tension on either side of a massless pulley must be the same. The tension on either side of a massless pulley must be different.Q1: The cable AB supports three vertical loads as shown in next figure. Compute the resultant of these three forces and locate it with respect to point (A). L4m 5m B. 20N 40 N 30 N
- A system of two cables supports a 1$0-N ball as shown. 30° 150 N What is the tension in the right-hand cable? A) 260 N B. 300 N C) 170 N 87 NDescribe the factors that cause static friction between two surfaces to increase.PROBLEM: Determine the tension in each cord in the figure shown. 389 N 38⁰ 62⁰ 55⁰ 35⁰ 525N