34. The speed of a hydraulic cylinder is controlled by means of a series pressure-compensated flow control valve, as shown in the given circuit. Given: Pump: V, - 25 cm'/rev п 1000 грm n, - 0.95 n. - 0.93 7, - 1 Directional control valve: Pa, Pla Q= 6×107JAP Relief valve: Cracking pressure = 6 MPa Override pressure 0 Hydraulic cylinder: P, f= 2000 Ns/m v = 0.1 m/s F = 9000 N Piston diameter = 60 mm Rod diameter = 25 mm No inner leakage Calculate: P=0 P, P, P, P Qu Qy Power losses in the DCV Power losses in the FCV (M- Pump real flow rate
34. The speed of a hydraulic cylinder is controlled by means of a series pressure-compensated flow control valve, as shown in the given circuit. Given: Pump: V, - 25 cm'/rev п 1000 грm n, - 0.95 n. - 0.93 7, - 1 Directional control valve: Pa, Pla Q= 6×107JAP Relief valve: Cracking pressure = 6 MPa Override pressure 0 Hydraulic cylinder: P, f= 2000 Ns/m v = 0.1 m/s F = 9000 N Piston diameter = 60 mm Rod diameter = 25 mm No inner leakage Calculate: P=0 P, P, P, P Qu Qy Power losses in the DCV Power losses in the FCV (M- Pump real flow rate
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:34. The speed of a hydraulic cylinder is controlled by means of a series
pressure-compensated flow control valve, as shown in the given circuit.
Given:
Pump:
V, = 25 cm'/rev
n = 1000 rpm
n, = 0.95
n. = 0.93
n. = 1
P,Q,
Pa,
Directional control valve:
Q= 6x10-7 VAP
Relief valve:
Cracking pressure = 6 MPa
P.
Override pressure = 0
P=0
Hydraulic cylinder:
f= 2000 Ns/m
v = 0.1 m/s
F= 9000 N
Piston diameter = 60 mm
Rod diameter = 25 mm
No inner leakage
Calculate:
P=0
P, P, P, Pp Qu Qy
Power losses in the DCV
M)
Power losses in the FCV
Pump real flow rate
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Follow-up Question
I confused following this picture why (3.85-1.033)*10^-6
Transcribed Image Text:6. Power loss in DCV
Q=6 × 10-7√√Ap
=6 × 10-7√(3.85 – 1.033) × 106
-3
=1.007 × 10-³ m³/s
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