33-54. Use a graphing calculator to verify the solutions toExercises 11-32.55. Find the z-value that corresponds to each percentile fora standard normal distribution.b) 50th percentilea) 30th percentilec) 95th percentile56. In a normal distribution with u = 60 and o = 7, findthe x-value that corresponds to thea) 35th percentileb) 75th percentile57. In a normal distribution with u = -15 and o = 0.4,find the x-value that corresponds to thea) 46th percentileb) 92nd percentile58. In a normal distribution with u = 0 and o = 4, findthe x-value that corresponds to thea) 50th percentileb) 84th percentile

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The histogram of the number of hours of sleep Stat 100 students reported getting each night roughly follows the normal curve with an average of 7.0 hours and a SD of 1.2 hours. a. Approximately 68% of the students sleep between hours and hot (Put the smaller number first) 提交答案|Tries 0/5 b. Approximately 95% of the students sleep between hours and hours. (Put the smaller number first) 提交答案| Tries 0/5 c. If a student sleeps 5.2 hours per night what percent of the people sleep more than her? Do the problem in steps: I. First, find the Z score = 提交答案|Tries 0/3 ii. Now, move the red vertical line on the following graph to the correct Z score by clicking and dragging the mouse. If you are using a touch screen, touch and then slide the region around the vertical line 1.00 Shade the region representing the percent of people who sleep more than her: Shade the region under the normal curve to the O left of the red vertical line O right of the red vertical line
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The arm span of a team of athletes was measured and listed in the attached image (Problem-Image2.jpg). a) Calculate the mean arm span, ?̄. b) Complete the table and calculate (to two decimal places of accuracy, the standard deviationof the data.). Check the equation in the attached image (Problem-Image3.jpg)
lustration 19.33. An examination was given to 50 students at College A and to 60 students at Collage B. At A, the mean grade was 75 with S.D.=9. At B, the mean was 79 with SD=7. Is there a significant difference in the performance at the two Colleges at 5% level of significance?
The ages of a random sample of motorcyclists when they were fatally injured in traffic crashes were recorded and tabled below: Age (in years) Below 16 1628 28 - < 40 40 - < 52 52 - < 64 64 - <76 B. 0.55 C. 0.44 Frequency 0 2 6 10 13 5 D. 0.50 Midpoints The relative frequency of motorcyclist's aged between 20 and 50 who were fatally injured in traffic crashes is (rounded off to two decimals): A. 0.38 22 34 46 58 70 Cumulative freq. 0 2 8 18 31 36
Assume the cholesterol levels of an adult can be described by a Normal model with a mean of 183 mg/dL and a standard deviation of 27. Complete parts a through e. b) What percent of adults do you expect to have cholesterol levels over 190 mg/dL? enter your response here % (Round to two decimal places as needed.) Part 3 c) What percent of adults do you expect to have cholesterol levels between 150 and 160 mg/dL? enter your response here % (Round to two decimal places as needed.) Part 4 d) Estimate the interquartile range of cholesterol levels. IQR=enter your response here mg/dL (Round to the nearest integer as needed.) Part 5 e) Above what value are the highest 15% of adults' cholesterol levels? enter your response here mg/dL (Round to the nearest integer as needed.)
6. Interval estimation when o is unknown (the data “Alcohol" is provided) Consumption of alcoholic beverages by young women of drinking age has been increas- ing in the United Kingdom, the United States, and Europe (The Wall Street Journal, Feb- ruary 15, 2006). Data (annual consumption in liters) consistent with the findings reported in The Wall Street Journal article are shown for a sample of 20 European young women. 266 82 199 174 97 170 222 115 130 169 164 102 113 171 93 93 110 130 Assuming the population is roughly symmetric, construct a 95% confidence interval for the mean annual consumption of alcoholic beverages by European young women.
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IQ tests supposedly measure our intelligence. They typically are ‘normed’ so that they have a mean of 100 and a standard deviation of 15. (Higher scores show higher intelligence.) Use the graph and use the z-score and percents from columns b and c in Table A, when relevant. If you scored 132, what is your z-score? (Interpret.) Use table A X, z(a), (b), and (c) X z (a) (b) (c) and use the graph! Write down or save your response to use in Part 2 of this quiz. Group of answer choices -2.53 z. I'm at the 98.34 percentile rank and 1.66% of people scored smarter than me. 2.13 z. I'm at the 98.34 percentile rank and 1.66% of people scored smarter than me. -2.13 z. I'm at the 1.66 percentile rank and 98.34% of people scored smarter than me. 2.53 z. I'm at the 0.57 percentile rank and 99.43% of people scored smarter than me. 2.13 z. I'm at the 1.66 percentile rank and 98.34% of people scored smarter than me. 2.53 z. I'm at the 99.43 percentile rank…
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