31(aq) + H,O2(aq) + 2H30*(aq)→5(aq)+ 4H0(1) Buffer O'H 10mL Rate TH Trial-1 0.03M 0.1M 0.2035M/s Trial-2 0.06M 0.0001M 10mL 0.1M 0.4072M/s Trial-3 0.03M 0.0002M 10mL 0,1M 0.2041M/s Trial-4 0.06M 0.0001M 10mL 0.2M 1.6290M/s Trial-5 0.03M 0.0001M 20mL 0.1M 0.2030M/s Trial-6 0.015M 0.0001M 10mL 0.1M 0.1018M/s

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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If I am given the attached information how would I go about finding the rate order for Iodine?
3r(aq) + H2O2(aq) + 2H3O*(aq) L(aq) + 4H2O(1)
HO
Buffer
Rate
TH
OH
Trial-1
0.03M
0.0001M
10mL
0.1M
0.2035M/s
Trial-2
0.06M
0.0001M
10mL
0.1M
0.4072M/s
Trial-3
0.03M
0.0002M
10mL
0.1M
0.2041M/s
Trial-4
0.06M
0.0001M
10mL
0.2M
1.6290M/s
Trial-5
0.03M
0.0001M
20mL
0.1M
0.2030M/s
Trial-6
0.015M
0.0001M
10mL
0.1M
0.1018M/s
Transcribed Image Text:3r(aq) + H2O2(aq) + 2H3O*(aq) L(aq) + 4H2O(1) HO Buffer Rate TH OH Trial-1 0.03M 0.0001M 10mL 0.1M 0.2035M/s Trial-2 0.06M 0.0001M 10mL 0.1M 0.4072M/s Trial-3 0.03M 0.0002M 10mL 0.1M 0.2041M/s Trial-4 0.06M 0.0001M 10mL 0.2M 1.6290M/s Trial-5 0.03M 0.0001M 20mL 0.1M 0.2030M/s Trial-6 0.015M 0.0001M 10mL 0.1M 0.1018M/s
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