(3112 GULICUU 5. The neutron flux in a bare spherical reactor of radius 50 cm is given by 2M (@) = 0 sin 0.0628r = 5 x 1013 OLDO mor where r is measured from the center of the reactor. The diffusion coefficient for the system is 0.80 cm. (a) What is the maximum value of the flux in the reactor? (b) Calculate the neutron current density as a function of position in the reactor. (c) How many neutrons escape from the reactor per second? leakage PA 1ps un dr -neutrons/cm²-sec,
(3112 GULICUU 5. The neutron flux in a bare spherical reactor of radius 50 cm is given by 2M (@) = 0 sin 0.0628r = 5 x 1013 OLDO mor where r is measured from the center of the reactor. The diffusion coefficient for the system is 0.80 cm. (a) What is the maximum value of the flux in the reactor? (b) Calculate the neutron current density as a function of position in the reactor. (c) How many neutrons escape from the reactor per second? leakage PA 1ps un dr -neutrons/cm²-sec,
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sin 0.0628r
= 5 x 1013
1000 mor
-neutrons/cm²-sec,
where r is measured from the center of the reactor. The diffusion coefficient
for the system is 0.80 cm. (a) What is the maximum value of the flux in the
reactor? (b) Calculate the neutron current density as a function of position in
the reactor. (c) How many neutrons escape from the reactor per second?
leakage
(@)&=0"
Transcribed Image Text:5. The neutron flux in a bare spherical reactor of radius 50 cm is given by
sin 0.0628r
= 5 x 1013
1000 mor
-neutrons/cm²-sec,
where r is measured from the center of the reactor. The diffusion coefficient
for the system is 0.80 cm. (a) What is the maximum value of the flux in the
reactor? (b) Calculate the neutron current density as a function of position in
the reactor. (c) How many neutrons escape from the reactor per second?
leakage
(@)&=0
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