31.0IA )One reaction scheme for producing ammonia, NH3, involves the reaction of methane (CH4), water, and nitrogen (N2) to form carbon dioxide and ammonia. - - Provide a balanced chemical equation for this synthesis route.
31.0IA )One reaction scheme for producing ammonia, NH3, involves the reaction of methane (CH4), water, and nitrogen (N2) to form carbon dioxide and ammonia. - - Provide a balanced chemical equation for this synthesis route.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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help me co eff using sytem of eq
Transcribed Image Text:One reaction scheme for producing ammonia, NH₃, involves the reaction of methane (CH₄), water, and nitrogen (N₂) to form carbon dioxide and ammonia. Provide a balanced chemical equation for this synthesis route.
![### Balancing Chemical Equations
#### Reaction:
\[ \text{CH}_4 + \text{H}_2\text{O} + \text{N}_2 \rightarrow \text{CO}_2 + \text{NH}_3 \]
- **Stoichiometric Coefficient (V):** Represents the number of moles for each substance in the reaction.
- Assume \( V_1 = -1 \).
#### Element Balance:
1. **Carbon (C):**
\[ V_1 + V_4 = 0 \]
\[ V_4 = 1 \]
2. **Hydrogen (H):**
\[ 4V_1 + 4V_2 + 4V_5 = 0 \]
3. **Oxygen (O):**
\[ 1V_2 + 2V_4 = 0 \]
4. **Nitrogen (N):**
\[ 2V_3 + 1V_5 = 0 \]
#### BCE:
Represents the process of Balancing Chemical Equations.
#### Complete Reaction:
\[ \_\_\_\text{CH}_4 + \_\_\_\text{H}_2\text{O} + \_\_\_\text{N}_2 \rightarrow \_\_\_\text{CO}_2 + \_\_\_\text{NH}_3 \]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F63f5865a-7713-44c4-be73-1c5678c4385b%2F2810e001-eafc-422c-8dcb-0d111fc0f627%2Fs16bvv_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Balancing Chemical Equations
#### Reaction:
\[ \text{CH}_4 + \text{H}_2\text{O} + \text{N}_2 \rightarrow \text{CO}_2 + \text{NH}_3 \]
- **Stoichiometric Coefficient (V):** Represents the number of moles for each substance in the reaction.
- Assume \( V_1 = -1 \).
#### Element Balance:
1. **Carbon (C):**
\[ V_1 + V_4 = 0 \]
\[ V_4 = 1 \]
2. **Hydrogen (H):**
\[ 4V_1 + 4V_2 + 4V_5 = 0 \]
3. **Oxygen (O):**
\[ 1V_2 + 2V_4 = 0 \]
4. **Nitrogen (N):**
\[ 2V_3 + 1V_5 = 0 \]
#### BCE:
Represents the process of Balancing Chemical Equations.
#### Complete Reaction:
\[ \_\_\_\text{CH}_4 + \_\_\_\text{H}_2\text{O} + \_\_\_\text{N}_2 \rightarrow \_\_\_\text{CO}_2 + \_\_\_\text{NH}_3 \]
Expert Solution
Step 1
In balanced reaction number of each atom on reactant side should be equal to number of each atom on product side. It is done by changing stiochiometry coefficient.
Step by step
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