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3+1 f(r) = 4r² – 1 g(x) = h(1) = VI 2т + 1 13. (f - 9)(г) Sz3 + 4x? – 3r – 4 (A) 2т +1 8r3 + 4r? – 1 +3 (C) 2т + 1 8r3 + 4x2 — т+2 (В) 2т + 1 (D) 8r3 + 4r2 -r+3 2т + 1 14. f(т) g(x) (A) 2г? + 51 — 3 (c) 2г? + 4г - 3 (D) 2r? – 4r +3 (В) 2л? — 5х —3 15. (fo f)(г) (А) 16х4 — - 8z2 (С) 64г* — 32г?+3 (В) 64т4 — 3212 + 4 (D) 1

3+1 f(r) = 4r² – 1 g(x) = h(1) = VI 2т + 1 13. (f - 9)(г) Sz3 + 4x? – 3r – 4 (A) 2т +1 8r3 + 4r? – 1 +3 (C) 2т + 1 8r3 + 4x2 — т+2 (В) 2т + 1 (D) 8r3 + 4r2 -r+3 2т + 1 14. f(т) g(x) (A) 2г? + 51 — 3 (c) 2г? + 4г - 3 (D) 2r? – 4r +3 (В) 2л? — 5х —3 15. (fo f)(г) (А) 16х4 — - 8z2 (С) 64г* — 32г?+3 (В) 64т4 — 3212 + 4 (D) 1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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s 13 14 15

3+1 f(r) = 4r² – 1 g(x) = h(r) = VI 2т + 1 13. (f - 9)(г) Sz3 + 4x? – 3r – 4 (A) 2т +1 8r3 + 4r? – 1 +3 (C) 2т + 1 8r3 + 4x2 — т+2 (В) 2т + 1 (D) 8r3 + 4r2 -r+3 2т + 1 14. f(т) g(x) (A) 2г? + 51 — 3 (c) 2г? + 4г - 3 (D) 2r? – 4r +3 (В) 2л? — 5х —3 15. (fo f)(г) (А) 16х4 — - 8z2 (С) 64г* — 32г?+3 (В) 64т4 — 3212 + 4 (D) 1
Transcribed Image Text:3+1 f(r) = 4r² – 1 g(x) = h(r) = VI 2т + 1 13. (f - 9)(г) Sz3 + 4x? – 3r – 4 (A) 2т +1 8r3 + 4r? – 1 +3 (C) 2т + 1 8r3 + 4x2 — т+2 (В) 2т + 1 (D) 8r3 + 4r2 -r+3 2т + 1 14. f(т) g(x) (A) 2г? + 51 — 3 (c) 2г? + 4г - 3 (D) 2r? – 4r +3 (В) 2л? — 5х —3 15. (fo f)(г) (А) 16х4 — - 8z2 (С) 64г* — 32г?+3 (В) 64т4 — 3212 + 4 (D) 1
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