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3000 lb/hr of coal is burned using 20 % excess air at a pressure of 14.7 psia and 70 o F. The ultimate analysis of coal is: Carbon = 66.1 %, Hydrogen = 6.03 %, Oxygen = 11.91 %, Nitrogen = 1.04 %, Sulflur = 2.4 %, Ash = 12.52 %. Determine: a) Air to fuel ratio by weight, b) wet and dry flue gas analysis, c) capacity required of a fan used to supply combustion air (ft 3 /min), d) Volume of flue gases at 14.7 psia and 200 o F, e) weight of CO 2 formed. PROBLEMS: 1. 3000 lb/hr of coal is burned using 20 % excess air at a pressure of 14.7 psia and 70 F. The ultimate analysis of coal is: Carbon = 66.1 %, Hydrogen = 6.03 %, Oxygen = 11.91 %, Nitrogen = 1.04 %, Sulflur = 2.4 %, Ash = 12.52 %. Determine: a) Air to fuel ratio by weight, b) wet and dry flue gas analysis, c) capacity required of a fan used to supply combustion air (ft/min), d) Volume of flue gases at 14.7 psia and 200 F, e) weight of CO, formed. %3D

3000 lb/hr of coal is burned using 20 % excess air at a pressure of 14.7 psia and 70 o F. The ultimate analysis of coal is: Carbon = 66.1 %, Hydrogen = 6.03 %, Oxygen = 11.91 %, Nitrogen = 1.04 %, Sulflur = 2.4 %, Ash = 12.52 %. Determine: a) Air to fuel ratio by weight, b) wet and dry flue gas analysis, c) capacity required of a fan used to supply combustion air (ft 3 /min), d) Volume of flue gases at 14.7 psia and 200 o F, e) weight of CO 2 formed. PROBLEMS: 1. 3000 lb/hr of coal is burned using 20 % excess air at a pressure of 14.7 psia and 70 F. The ultimate analysis of coal is: Carbon = 66.1 %, Hydrogen = 6.03 %, Oxygen = 11.91 %, Nitrogen = 1.04 %, Sulflur = 2.4 %, Ash = 12.52 %. Determine: a) Air to fuel ratio by weight, b) wet and dry flue gas analysis, c) capacity required of a fan used to supply combustion air (ft/min), d) Volume of flue gases at 14.7 psia and 200 F, e) weight of CO, formed. %3D

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
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3000 lb/hr of coal is burned using 20 % excess air at a pressure of 14.7 psia and 70 o F. The ultimate analysis of coal is: Carbon = 66.1 %, Hydrogen = 6.03 %, Oxygen = 11.91 %, Nitrogen = 1.04 %, Sulflur = 2.4 %, Ash = 12.52 %. Determine: a) Air to fuel ratio by weight, b) wet and dry flue gas analysis, c) capacity required of a fan used to supply combustion air (ft 3 /min), d) Volume of flue gases at 14.7 psia and 200 o F, e) weight of CO 2 formed. PROBLEMS: 1. 3000 lb/hr of coal is burned using 20 % excess air at a pressure of 14.7 psia and 70 F. The ultimate analysis of coal is: Carbon = 66.1 %, Hydrogen = 6.03 %, Oxygen = 11.91 %, Nitrogen = 1.04 %, Sulflur = 2.4 %, Ash = 12.52 %. Determine: a) Air to fuel ratio by weight, b) wet and dry flue gas analysis, c) capacity required of a fan used to supply combustion air (ft'/min), d) Volume of flue gases at 14.7 psia and 200 F, e) weight of CO, formed. %3D
Transcribed Image Text:3000 lb/hr of coal is burned using 20 % excess air at a pressure of 14.7 psia and 70 o F. The ultimate analysis of coal is: Carbon = 66.1 %, Hydrogen = 6.03 %, Oxygen = 11.91 %, Nitrogen = 1.04 %, Sulflur = 2.4 %, Ash = 12.52 %. Determine: a) Air to fuel ratio by weight, b) wet and dry flue gas analysis, c) capacity required of a fan used to supply combustion air (ft 3 /min), d) Volume of flue gases at 14.7 psia and 200 o F, e) weight of CO 2 formed. PROBLEMS: 1. 3000 lb/hr of coal is burned using 20 % excess air at a pressure of 14.7 psia and 70 F. The ultimate analysis of coal is: Carbon = 66.1 %, Hydrogen = 6.03 %, Oxygen = 11.91 %, Nitrogen = 1.04 %, Sulflur = 2.4 %, Ash = 12.52 %. Determine: a) Air to fuel ratio by weight, b) wet and dry flue gas analysis, c) capacity required of a fan used to supply combustion air (ft'/min), d) Volume of flue gases at 14.7 psia and 200 F, e) weight of CO, formed. %3D
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