300 За 275.6 C; 6.00MPA 200 100 I/x = 0 41.5°C: 0.008 MPa 4 x = | 3 4 5 7 9 10 nuclear-power.net Specific Entropy [k]/kgK Steam turbine W, Rankine cycle Heat Condenser exchanger Feedwater W pump Wr - Wp QH QH - Qc Calculate: 1. the vapor quality of the outlet steam 2. the enthalpy difference between these two states (3 - 4), which corresponds to the work done by the steam, Wr. 3. the enthalpy difference between these two states (1 - 2), which corresponds to the work done by pumps, Wp.
300 За 275.6 C; 6.00MPA 200 100 I/x = 0 41.5°C: 0.008 MPa 4 x = | 3 4 5 7 9 10 nuclear-power.net Specific Entropy [k]/kgK Steam turbine W, Rankine cycle Heat Condenser exchanger Feedwater W pump Wr - Wp QH QH - Qc Calculate: 1. the vapor quality of the outlet steam 2. the enthalpy difference between these two states (3 - 4), which corresponds to the work done by the steam, Wr. 3. the enthalpy difference between these two states (1 - 2), which corresponds to the work done by pumps, Wp.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
i need the answer quickly
![300
За
3
275.6°C: 6.00MPA
200
100
I/x = 0
41.5°C: 0.008 MPa
x = |
2
3
4
6.
8.
10
nuclear-power.net
Specific Entropy [k]/kgK
Steam turbine
W,
3
4
Rankine cycle
Нeat
2
exchanger
Condenser
Feedwater W.
pump
Wr - Wp
QH - Qc
QH
Calculate:
1. the vapor quality of the outlet steam
2. the enthalpy difference between these two states (3 - 4),
which corresponds to the work done by the steam, W-.
3. the enthalpy difference between these two states (1
which corresponds to the work done by pumps, Wp.
4. the enthalpy difference between these two states (2
2),
- 3),
which corresponds to the net heat added in the steam
generator
5. the thermodynamic efficiency of this cycle and compare
this value with the Carnot's efficiency](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd20be041-8d41-498e-876a-de65658a7b14%2Ff7f0814d-5e00-4d10-ad32-473b3b27597f%2Fodp86cd_processed.jpeg&w=3840&q=75)
Transcribed Image Text:300
За
3
275.6°C: 6.00MPA
200
100
I/x = 0
41.5°C: 0.008 MPa
x = |
2
3
4
6.
8.
10
nuclear-power.net
Specific Entropy [k]/kgK
Steam turbine
W,
3
4
Rankine cycle
Нeat
2
exchanger
Condenser
Feedwater W.
pump
Wr - Wp
QH - Qc
QH
Calculate:
1. the vapor quality of the outlet steam
2. the enthalpy difference between these two states (3 - 4),
which corresponds to the work done by the steam, W-.
3. the enthalpy difference between these two states (1
which corresponds to the work done by pumps, Wp.
4. the enthalpy difference between these two states (2
2),
- 3),
which corresponds to the net heat added in the steam
generator
5. the thermodynamic efficiency of this cycle and compare
this value with the Carnot's efficiency
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