**Page 93**30. Robberies Find the sample size needed to estimate the percentage of robberies in Texas that result in arrests. Use a 0.04 margin of error, use a confidence level of 80%, and assume that $ \hat{p} $ and $ \hat{q} $ are unknown.32. Fortune Tellers Find the sample size needed to estimate the percentage of adults who have consulted fortune tellers. Use a 0.03 margin of error, use a confidence level of 98%, and use results from a prior Pew Research Center poll suggesting that 15% of adults have consulted fortune tellers.34. Windows Penetration You plan to develop a new software system that you believe will surpass the success of Google and Facebook combined. In planning for the operating system that you will use, you need to estimate the percentage of computers that use Windows. How many computers must be surveyed in order to be 99% confident that your estimate is in error by no more than one percentage point?a. Assume that nothing is known about the percentage of computers with Windows operating systems.b. Assume that a recent survey suggests that about 90% of computers use Windows operating systems (based on data from Net Applications).c. Does the additional survey information from part (b) have much of an effect on the sample size that is required?

Answered: Image /qna-images/answer/fcb9ca2f-a989-4c26-a193-9f76865e5dc2.jpg

30. Robberies Find the sample size needed to estimate the percentage of robberies in Texas that result in arrests. Use a 0.04 margin of error, use a confidence level of 80%, and assume that p and â are unknown.

30. Robberies Find the sample size needed to estimate the percentage of robberies in Texas that result in arrests. Use a 0.04 margin of error, use a confidence level of 80%, and assume that p and â are unknown.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Find the sample size need to find the Population Mean if the margin of error is $105, the confidence…

A: Solution: From the given information, confidence level is 0.95, σ=315 and E=105.

Q: d the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: Margin of error E=4%=0.04C.I=95%=0.95

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: a)

Q: What set of factors would produce the narrowest confidence interval for estimating a poulation mean?…

A: Objective of this question is that, which option is the correct choice.

Q: Use the sample data and confidence level given below to complete parts (c). A research institute…

A: It is given that, the number of respondents said yes (x) is 587 and the sample size (n) is 912. The…

Q: Use the given confidence interval to find the margin of error and the sample proportion. (0.704,…

A: The confidence interval for population proportion is given by (0.704, 0.732)

Q: A professor is interested in how attendance influences grades her class. She goes through her…

A: 1) Given Data : We will calculate the point estimate which will be the mean of this sample data,…

Q: Suppose the 95% confidence interval for a population mean is (20.5, 35.5). What is the margin of…

Q: You must estimate the mean temperature (in degrees Fahrenheit) with the following sample…

A: Obtain the 99% confidence interval for the population mean temperature. The 99% confidence interval…

Q: B. Find the margin error that corresponds to the given statistics and confidence level. n = 150, p =…

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: Step 1: Given informationConfidence level, c = 0.90Margin of error, E = 0.05 Step 2: Part (a)The…

Q: 14. Direct Mail A survey shows that 51% of adults prefer to receive advertisements through the mail.…

A: Given percent of adults prefer to receive advertisements through the mail=51%Margin of error(E)=5.2%

Q: UCLA would like to conduct a study to estimate the proportion of all UCLA students attending…

A: The value of margin of error is, Critical values: Using the z-table, the critical value at 98%…

Q: To estimate the proportion of smoker a sample of 100 men was selected. In the selected sample, 40…

Q: Use the sample data and confidence level to construct the confidence interval estimate of the…

A: n=1200 x=900 CI=99% α=1-0.99=0.01

Q: Suppose the 90% confidence interval for a population mean is (20, 55). What is the point estimate…

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: given data, E= 2%CI=0.90α=1-0.90=0.10for 90% CI, z-critical value:Zc:=Z0.10/2=Z0.05=1.645 [ from…

Q: Use the given data to find the minimum sample size required to estimaate the population proportion.…

A: As p and q are unknown, consider the values of p and q as 0.5.

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

Q: Refer to the data below: To estimate the mean height of female high school juniors, you take a…

A: Solution: Given data Sample size(n) = 30 To find : Point Estimate of mean (μ) =??

Q: estimate of for the following. E = .17, ? = .90, confidence level = 99%

A: (1) We have given that, Population proportion (p) = 0.90, margin of error (E) = 0.17 and…

Q: When 307 college students are randomly selected and surveyed, it is found that 128 own a car. Find a…

A: Given Data Sample Size, n = 307 Number of successes, x = 128 Significance level,…

Q: Use the Student's t distribution to find tc for a 95% confidence level when the sample size is 6.…

A: According to the given information, We have 95% confidence level Sample size, n = 6

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

Q: The baseball coach tracked how long it took 8 of his players to do a series of drills. The times…

A: We have given the times recorded (in minutes) of 8 players.

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: margin of error(E)=0.05Assume sample…

Q: Use the given data to find the minimum sample size required to estimate the population proportion.…

A: The confidence level is 93% Therefore, α = 0.07 and α/2=0.035. The margin of error is 0.002 Since…

Q: assume that a sample is used to estimate a population proportion p. find the margin of error that…

A: Givensample size(n)=325x=54.2p^=xn=54.2325=0.1668confidence level = 95%

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Obtain the 99% confidence interval for the true proportion of all college students who own a car.…

Q: The annual earnings (in dollars) of 35 randomly selected microbiologists are shown in the data…

A: From the provided information, Sample size (n) = 35 Confidence level = 98%

Q: Refer back to the pizza-delivery Try It exercise. The mean delivery time is 36 minutes and the…

A: Here the given information is The mean delivery time is 36 minutes and the population standard…

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: GIVEN DATA,margin of error =1%=0.01CI=0.95α=1-0.95=0.05Zc=Zα/2=Z0.05/2=Z0.025=1.96 [ from excel…

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: Margin of error(E)=4%=0.04confidence level=99%

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given, Lower bound = 0.39 Upper bound = 0.78 Here, we use to determine the margin of error.

Q: Assume that a sample is used to estimate a population proportion p. Find the margin of error M.E.…

A: Solution: Given information: n= 220 Sample size x= 110 successes p^=xn=110220= 0.5 Sample…

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: Margin of error E=2%=0.02C.I=99%=0.99

Q: Use the given confidence interval to find the margin of error and the sample proportion.…

A: Confidence interval (0.761,0.785)

Q: A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and…

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

**Page 93**

30. Robberies
Find the sample size needed to estimate the percentage of robberies in Texas that result in arrests. Use a 0.04 margin of error, use a confidence level of 80%, and assume that $ \hat{p} $ and $ \hat{q} $ are unknown.

32. Fortune Tellers
Find the sample size needed to estimate the percentage of adults who have consulted fortune tellers. Use a 0.03 margin of error, use a confidence level of 98%, and use results from a prior Pew Research Center poll suggesting that 15% of adults have consulted fortune tellers.

34. Windows Penetration
You plan to develop a new software system that you believe will surpass the success of Google and Facebook combined. In planning for the operating system that you will use, you need to estimate the percentage of computers that use Windows. How many computers must be surveyed in order to be 99% confident that your estimate is in error by no more than one percentage point?

a. Assume that nothing is known about the percentage of computers with Windows operating systems.

b. Assume that a recent survey suggests that about 90% of computers use Windows operating systems (based on data from Net Applications).

c. Does the additional survey information from part (b) have much of an effect on the sample size that is required?

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

$Point Estimation, Limit Theorems, Approximations, and Bounds$

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, statistics and related others by exploring similar questions and additional content below.

Similar questions

Use a 0.02 margin of error and use a confidence level of 90%. Complete parts (a) through (c) below.
In a sample survey, 138 students failed the exam out of 200 total students. 1. Calculate the 95% confidence interval for the population prportion of students who failed the exam. 2. Compare the margin of errors at 90%, 95%, and 99% confidence intervals. What happens when the confidence interval increases?
8. Construct the confidence interval for the population variance for the given values. Round your answers to one decimal place. Answer: Lower endpoint: n = 24, s² = 3.9, and c = 0.99 Upper endpoint:
4. Probability help me uhuhuhuh
Determine the t values that correspond to the boundaries for the confidence level desired. If the desired confidence level is 80%, for a sample of n=31 individuals, what t values form the boundaries for the middle 80% and the most extreme 20%?
Subject - account Please help me. Thankyou.
Find the sample size needed to estimate the percentage of residents of one region of a country who are left-handed. Use a margin of error of six percentage points, and use a confidence level of 99%. Complete parts (a) through (c) below.
Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 3 percentage points and use a confidence level of 95%. Complete parts (a) and (b) below. a. Assume that p and q are unknown. n= (Round up to the nearest integer.) b. Assume that 25% of adults can wiggle their ears. n= (Round up to the nearest integer.) C
Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 3 percentage points and use a confidence level of 90%. Complete parts (a) and (b) below. a. Assume that p and q are unknown. n= (Round up to the nearest integer.)
find the sample size needed to estimate the percentage of adults who can wiggle their ears. use a margin of error of 4 percentage and use a confidence level of 95%. complete parts (a) and (b) below. b. assume that 21% of adults can wiggle their ears. b. Assume that 21% of adults can wiggle their ears
Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 5 percentage points and use a confidence level of 90%. Complete parts (a) and (b) below. a. Assume that p and q are unknown. n = (Round up to the nearest integer.)
find the sample size if you have : margin of error =0.311 confidence level =95% p=0.5