30. Calculate the emf of the following cell at 298 K: Al(s)/Al3+ (0.15M)//Cu2 (0.025M) /Cu(s) (Given E (Al3 /Al) -1.66 V, E (Cu2/Cu) 0.34V, log 0.15 = -0.8239, log 0.025 = -1.6020) %3D
30. Calculate the emf of the following cell at 298 K: Al(s)/Al3+ (0.15M)//Cu2 (0.025M) /Cu(s) (Given E (Al3 /Al) -1.66 V, E (Cu2/Cu) 0.34V, log 0.15 = -0.8239, log 0.025 = -1.6020) %3D
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.64QE
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![• Question
30. Calculate the emf of the following cell at 298 K:
Al(s)/Al3+ (0.15M)//Cu2 (0.025M) /Cu(s)
(Given E(A13 /AI) = -1.66 V, E (Cu2/Cu) 0.34V, log 0.15 = -0.8239, log 0.025 =
-1.6020)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb587a1b5-36b4-4a32-a743-edf570a5b30b%2Ff0e4c71f-c0b0-4788-b594-e625c2d0091d%2Fzzl94ea_processed.jpeg&w=3840&q=75)
Transcribed Image Text:• Question
30. Calculate the emf of the following cell at 298 K:
Al(s)/Al3+ (0.15M)//Cu2 (0.025M) /Cu(s)
(Given E(A13 /AI) = -1.66 V, E (Cu2/Cu) 0.34V, log 0.15 = -0.8239, log 0.025 =
-1.6020)
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