Answered: 30 mm 120 mm D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

The shaft-disk-belt arrangement shown is used to transmit 2.4 kW from point A to point D. Knowing that the maximum allowable couples that can be applied to shafts AB and CD are 25 N.m and 80 N.m, respectively, determine the required minimum speed of shaft AB.

Expert Solution

Step 1

Given,

Power Transmitted P=2.4KW

Maximum allowable torque on shaft AB=25Nm

Maximum allowable torque on shaft DC=80Nm

Speed of the shaft AB based on maximum allowable torque on shaft AB

since,

$P = T ω_{1} ω_{1} = \frac{2400}{25} = 96 r a d / s \sin c e, \frac{ω_{1}}{ω_{2}} = \frac{D_{2}}{D_{1}} ω_{2} = \frac{D_{1}}{D_{2}} \times ω_{1} ω_{2} = \frac{30}{120} \times 96 = 24 r a d / s$

Compute the torque produced at shaft DC due to this speed

$P = T_{2} ω_{2} T_{2} = \frac{2400}{24} = 100 N m$

This is more than allowable torque 80Nm for shaft DC,

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