Common-Collector Configuration problem. Answer no. 26 onlyReference: Electronic device and circuit theory 11th edition by Boylestad 3.6 COMMON-COLLECTOR CONFIGURATIONThe third and final transistor configuration is the common-collector configuration, shownin Fig. 3.20 with the proper current directions and voltage notation. The common-collectorconfiguration is used primarily for impedance-matching purposes since it has a high inputimpedance and low output impedance, opposite to that of the common-base and common-emitter configurations.(b)FIG. 3.20Notation and symbots used with the common-collector configuration: (a) pup transistor;(b) apa transistor.A common-collector cireuit configuration is provided in Fig. 3.21 with the load resistorconnected from emitter to ground. Note that the collector is tied to ground even though thetransistor is connected in a manner similar to the common emitter configuration. From adesign viewpoint, there is no need for a set of common-collector characteristics to choosethe parameters of the circuit of Fig. 3.21. It can be designed using the common-emittercharacteristics of Section 3.5. For all practical purposes, the output characteristics of thecommon-collector configuration are the same as for the common-emitter configuration. Forthe common-collector configuration the output characteristics are a plot of Ig versus VCEfor a range of values of I, The input current, therefore, is the same for both the common-emitter and common-collector characteristics. The horizontal voltage axis for the common-collector configuration is obtained by simply changing the sign of the collector-to-emittervoltage of the common-emitter characteristics. Finally, there is an almost unnoticeableFIG. 3.21Comon-collector configurationused for impedance-marchingpurposes. b. Find the value of a corresponding to this operating point.c. At VCE = +6 V, find the corresponding value of ICEo-d. Calculate the approximate value of ICBO using the de beta value obtained in part (a).*20. a. Using the characteristics of Fig. 3.13a, determine IcEO at VcE = 10 V.b. Determine Bac at Ig = 10 µA and VcE = 10 V.c. Using the Bac determined in part (b), calculate IcBo-21. a. Using the characteristics of Fig. 3.13a, determine Bg, at lg = 60 µA and Vcg = 4 V.b. Repeat part (a) at Ig = 30 µA and VcE = 7 V.c. Repeat part (a) at Ig = 10 µA and VcE = 10 V.d. Reviewing the results of parts (a) through (c), does the value of Bg. change from point to pointon the characteristics? Where were the higher values found? Can you develop any general con-clusions about the value of Ba: on a set of characteristics such as those provided in Fig. 3.13a?*22. a. Using the characteristics of Fig. 3.13a, determine Byc at Ig = 60 µA and VcE = 4 V.b. Repeat part (a) at Ig = 30 µA and VcE =7 V.c. Repeat part (a) at Ig = 10 µA and VCE = 10 V.d. Reviewing the results of parts (a) through (c), does the value of Bac change from point topoint on the characteristics? Where are the high values located? Can you develop any gen-eral conclusions about the value of Bac On a set of collector characteristics?e. The chosen points in this exercise are the same as those employed in Problem 21. If Prob-lem 21 was performed, compare the levels of Bac and Bac for each point and comment onthe trend in magnitude for each quantity.23. Using the characteristics of Fig. 3.13a, determine Ba, at Ig = 25 µA and VcE = 10 V. Thencalculate ag and the resulting level of Ig. (Use the level of Ic determined by Ic = Bap.)24. a. Given that ase = 0.980, determine the corresponding value of Bac-b. Given Bac = 120, determine the corresponding value of a.c. Given that Bác = 120 and Ic = 2.0 mA, find Ig and Ig.25. From memory only, sketch the common-emitter configuration (for npn and pnp) and insert theproper biasing arrangement with the resulting current directions for Ig. Ic, and Ig.3.6 Common-Collector Configuration26. An input voltage of 2 V rms (measured from base to ground) is applied to the circuit of Fig. 3.21.Assuming that the emitter voltage follows the base voltage exactly and that Ve (rms) = 0.1 V,calculate the circuit voltage amplification (A, = V,/V) and emitter current for Rg = 1 kN.

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Answered: 3.6 Common-Collector Configuration 26.…

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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