Answered: 3.5m Silty sand; y = 18,5 kN/m? GWT…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Question

3.5m:
Silty sand; y=18,5 kN/m?
GWT
Sub-layer 1
Sub-layer 2
Lean Clay (CL); y= 16.5 kN/m³
o= 150kPa, C = 0.14,
16.0m
CR= 0.025 and e, = 0.5
Sub-layer 3
Sub-layer 4

Transcribed Image Text:A compacted soil fill with thickness 5 m and total unit weight of 20.5 kN/m° is placed at the ground level at a construction site with the above soil profile. It is necessary to determine the consolidation settlement within the lean clay (CL) due to the placement of the soil fill. For this purpose, the 16 m thick clay layer has been subdivided into 4 sub-layers of equal thickness (i.e., 4 m thick sub- layers). Unit weight of water = 9.81 kN/m³. In this problem you are asked to perform necessary calculation for Sub-layer 3 a) Vertical effective stress at mid-depth of Sub-layer 3 before loading (in kPa) = ..(Report to nearest ONE decimal) b) Vertical effective stress at mid-depth of Sub-layer 3 after loading (in kPa) = ..(Report to nearest ONE decimal) c) The correct equation to calculate consolidation settlement in Sub-layer 3 is (Equation 1/Equation 2/Equation 3) H. ΔΗ 1+e T Colog Po+Ap Po Equation 1 Ho ΔΗ- 1+el Po+4p Equation 2 CR log %3D Po H. ΔΗ 1+e T Calog+ Colog.+Ap 수Galog는+ Colog. Equation 3 Pe d) The consolidation settlement in Sub-layer 3 is (in mm) = .(Report to nearest whole number)

Expert Solution

Trending now

This is a popular solution!

Step by step

Solved in 2 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Stresses in saturated soil without seepage

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions