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3.31 (a) The test circuit of Fig. P3.30 is adjusted so that VSG = VBS = 0. Given that I = 240 μA for VSD = 8 V, ID=210 μA for VSD = 2 V, and ID = 150 μA for VSD = 0.5 V, and given that I drops to zero if VBS is raised to 6 V, identify the device type (enhancement or depletion?) and find V₁o, k, y, and λ. Assume = 0.35 V. (b) Predict I, with VSG = VBS = VSD = 2 V.

3.31 (a) The test circuit of Fig. P3.30 is adjusted so that VSG = VBS = 0. Given that I = 240 μA for VSD = 8 V, ID=210 μA for VSD = 2 V, and ID = 150 μA for VSD = 0.5 V, and given that I drops to zero if VBS is raised to 6 V, identify the device type (enhancement or depletion?) and find V₁o, k, y, and λ. Assume = 0.35 V. (b) Predict I, with VSG = VBS = VSD = 2 V.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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3. 31
VSG + G 마 SO DO FIGURE P3.30 B + -VBS ID -VSD
Transcribed Image Text:VSG + G 마 SO DO FIGURE P3.30 B + -VBS ID -VSD
3.31 (a) The test circuit of Fig. P3.30 is adjusted so that VSG = VBS = 0. Given that I = 240 μA for VSD = 8 V, ID = 210 μA for VSD = 2 V, and ID = 150 μA for VSD = 0.5 V, and given that I drops to zero if VBS is raised to 6 V, identify the device type (enhancement or depletion?) and find V₁0, k, y, and λ. Assume = 0.35 V. (b) Predict In with VSG = VBS = VSD = 2 V.
Transcribed Image Text:3.31 (a) The test circuit of Fig. P3.30 is adjusted so that VSG = VBS = 0. Given that I = 240 μA for VSD = 8 V, ID = 210 μA for VSD = 2 V, and ID = 150 μA for VSD = 0.5 V, and given that I drops to zero if VBS is raised to 6 V, identify the device type (enhancement or depletion?) and find V₁0, k, y, and λ. Assume = 0.35 V. (b) Predict In with VSG = VBS = VSD = 2 V.
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