(3.10: Similar to Example 3.17 & 18)Find the empirical formula of a compound containing 36.86% nitrogen and 63.14% oxygen by mass. O N₂O O N₂O3 O NO₂ O N304

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### Determining the Empirical Formula

#### Problem Statement:
*Example 3.10*: Similar to Example 3.17 & 18, find the empirical formula of a compound containing 36.86% nitrogen and 63.14% oxygen by mass.

#### Options:
- \( \text{N}_2\text{O} \)
- \( \text{N}_2\text{O}_3 \)
- \( \text{NO}_2 \)
- \( \text{N}_3\text{O}_4 \)

#### Explanation for Calculation:
To find the empirical formula, follow these steps:
1. **Convert Percentages to Grams**: Assume you have 100 grams of the compound, which means you have 36.86 grams of nitrogen (N) and 63.14 grams of oxygen (O).
   
2. **Convert Grams to Moles**:
   - Moles of \( \text{N} \) = \( \frac{36.86 \text{ g}}{14.01 \text{ g/mol}} \)
   - Moles of \( \text{O} \) = \( \frac{63.14 \text{ g}}{16.00 \text{ g/mol}} \)

3. **Calculate the Mole Ratio**:
   - Determine the ratio by dividing each mole value by the smallest number of moles calculated.
   
4. **Derive the Empirical Formula**:
   - Use the mole ratio to write the empirical formula of the compound. 

Consult the examples mentioned (Example 3.17 and 18) for step-by-step procedures of similar problems to aid in your understanding.
Transcribed Image Text:### Determining the Empirical Formula #### Problem Statement: *Example 3.10*: Similar to Example 3.17 & 18, find the empirical formula of a compound containing 36.86% nitrogen and 63.14% oxygen by mass. #### Options: - \( \text{N}_2\text{O} \) - \( \text{N}_2\text{O}_3 \) - \( \text{NO}_2 \) - \( \text{N}_3\text{O}_4 \) #### Explanation for Calculation: To find the empirical formula, follow these steps: 1. **Convert Percentages to Grams**: Assume you have 100 grams of the compound, which means you have 36.86 grams of nitrogen (N) and 63.14 grams of oxygen (O). 2. **Convert Grams to Moles**: - Moles of \( \text{N} \) = \( \frac{36.86 \text{ g}}{14.01 \text{ g/mol}} \) - Moles of \( \text{O} \) = \( \frac{63.14 \text{ g}}{16.00 \text{ g/mol}} \) 3. **Calculate the Mole Ratio**: - Determine the ratio by dividing each mole value by the smallest number of moles calculated. 4. **Derive the Empirical Formula**: - Use the mole ratio to write the empirical formula of the compound. Consult the examples mentioned (Example 3.17 and 18) for step-by-step procedures of similar problems to aid in your understanding.
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