Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Hi could you please do question 3?
![Molecule 1
HH
H-O-C-C-O-H
II
Η Η
I-U-I I
Molecule 3
Η Η
HICIC-H
HH
II
-C-C
I
H
H-C-H H-C-H
I
Molecule 5
O=C=O
n
Answer:
F₁
"
>H-O-C-C-0-H
H H
F
Molecule 2
C=C
Molecule 4
HHH
III
H-C-C-C-0₁
I
| |
HHH
1. Identify a reaction type that could be used to produce each molecule.
molecule #1 - Substitution
molecule #2- elimination
Answer: molecule #3 - addition
molecule #4 - esterification
molecule #5 - combustion
0²
0
2. Write the balanced chemical equation for the production of each molecule using the
reaction type identified in question 1.
HHH
1)
O
+ H₂0, H¹
H
HIC-H
H
C-C-H
0
4)H-C-C-C-0-H + H-C-C-OH-> H-L-C-C-0-C-C-H + H-O-H
HHH
HHN
H
5) H-C-4 + 20₂ -> 0=C=0 + 2H₂0
Answer:
=>
F
+2HF
[2) CHF = -².2
heat
E
F-
->
3) (---) —> [m 3] - [H
H-C-H
3. Write the name of the reactants and products developed in your answer to question 2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb5fdd233-e947-4d5f-a3c0-4edca06f47b3%2F90ca70de-9358-473b-b18e-afd669d962ca%2Fw5wbszq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Molecule 1
HH
H-O-C-C-O-H
II
Η Η
I-U-I I
Molecule 3
Η Η
HICIC-H
HH
II
-C-C
I
H
H-C-H H-C-H
I
Molecule 5
O=C=O
n
Answer:
F₁
"
>H-O-C-C-0-H
H H
F
Molecule 2
C=C
Molecule 4
HHH
III
H-C-C-C-0₁
I
| |
HHH
1. Identify a reaction type that could be used to produce each molecule.
molecule #1 - Substitution
molecule #2- elimination
Answer: molecule #3 - addition
molecule #4 - esterification
molecule #5 - combustion
0²
0
2. Write the balanced chemical equation for the production of each molecule using the
reaction type identified in question 1.
HHH
1)
O
+ H₂0, H¹
H
HIC-H
H
C-C-H
0
4)H-C-C-C-0-H + H-C-C-OH-> H-L-C-C-0-C-C-H + H-O-H
HHH
HHN
H
5) H-C-4 + 20₂ -> 0=C=0 + 2H₂0
Answer:
=>
F
+2HF
[2) CHF = -².2
heat
E
F-
->
3) (---) —> [m 3] - [H
H-C-H
3. Write the name of the reactants and products developed in your answer to question 2.
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