3. Write the genotype of the gametes for the following parent plants (use the pea plant traits): Gametes a. Ss b. C. SsYy OOOO d. PPAa Hint for c and d (dihybrid case): Each gamete needs a pair of different letters due to the law of segregation.

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**Transcription and Diagram Explanation**

**3. Write the genotype of the gametes for the following parent plants (use the pea plant traits):**

**Gametes:**

- a. **Ss**

  The parent plant with genotype Ss will produce the following gametes:
  
  - S
  - s
  
- b. **SS**

  The parent plant with genotype SS will produce the following gamete:
  
  - S (only one type since both alleles are the same)

- c. **SsYy**

  The parent plant with genotype SsYy will produce the following gametes, due to the dihybrid nature:

  - SY
  - Sy
  - sY
  - sy

- d. **PPAa**

  The parent plant with genotype PPAa will produce the following gametes:

  - PA
  - Pa

**Hint for c and d (dihybrid case):** Each gamete needs a pair of different letters due to the law of segregation.

**Diagrams:**

Each plant genotype is represented by a circle containing its alleles. For the single trait cases (a and b), there are single circles showing two potential alleles or a single type. For the dihybrid cases (c and d), the circles are arranged to show the combinations of alleles that result from the law of segregation, ensuring that each gamete receives one allele for each trait.
Transcribed Image Text:**Transcription and Diagram Explanation** **3. Write the genotype of the gametes for the following parent plants (use the pea plant traits):** **Gametes:** - a. **Ss** The parent plant with genotype Ss will produce the following gametes: - S - s - b. **SS** The parent plant with genotype SS will produce the following gamete: - S (only one type since both alleles are the same) - c. **SsYy** The parent plant with genotype SsYy will produce the following gametes, due to the dihybrid nature: - SY - Sy - sY - sy - d. **PPAa** The parent plant with genotype PPAa will produce the following gametes: - PA - Pa **Hint for c and d (dihybrid case):** Each gamete needs a pair of different letters due to the law of segregation. **Diagrams:** Each plant genotype is represented by a circle containing its alleles. For the single trait cases (a and b), there are single circles showing two potential alleles or a single type. For the dihybrid cases (c and d), the circles are arranged to show the combinations of alleles that result from the law of segregation, ensuring that each gamete receives one allele for each trait.
**Activity 10.2: Genetics Problems**

Use the following information about pea plants from Mendel's experiments:

| **Dominant Trait** | **Recessive Trait** |
|--------------------|---------------------|
| S = spherical seeds | s = wrinkled seeds |
| Y = yellow seeds    | y = green seeds    |
| P = purple flowers  | p = white flowers  |
| I = inflated pods   | i = constricted pods |

This table categorizes traits observed in Mendel’s pea plant experiments into dominant and recessive types. Dominant traits are expressed when at least one dominant allele is present, while recessive traits appear only when both alleles are recessive.
Transcribed Image Text:**Activity 10.2: Genetics Problems** Use the following information about pea plants from Mendel's experiments: | **Dominant Trait** | **Recessive Trait** | |--------------------|---------------------| | S = spherical seeds | s = wrinkled seeds | | Y = yellow seeds | y = green seeds | | P = purple flowers | p = white flowers | | I = inflated pods | i = constricted pods | This table categorizes traits observed in Mendel’s pea plant experiments into dominant and recessive types. Dominant traits are expressed when at least one dominant allele is present, while recessive traits appear only when both alleles are recessive.
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