### Nucleophilic Properties in Organic Compounds**Question: 3. Which of the following are nucleophiles?**The image presents four different organic compounds labeled 1 through 4. Below is a detailed description of each compound shown:1. **Compound 1**: This is a hydrocarbon with a double bond (alkene) and a branching methyl group, commonly referred to as isobutene or 2-methylpropene. The structure is: ``` CH3 | CH2=C-CH3 ```2. **Compound 2**: This is methylamine (CH\(_3\)NH\(_2\)), an amine where a methyl group is bonded to an amino group (-NH2).3. **Compound 3**: This is methoxide ion (CH\(_3\)O\(^-\)), an oxygen anion with a methyl group attached, carrying a negative charge.4. **Compound 4**: This is 1-butyne (H3C-C≡C-H), an alkyne containing a triple bond between carbons.In order to identify which of these compounds act as nucleophiles, it's important to understand what a nucleophile is. A nucleophile is a species that donates an electron pair to form a chemical bond in relation to a reaction. Generally, nucleophiles have lone pairs of electrons or are negatively charged.### Analysis:- Compounds 2 and 3 are the nucleophiles since both contain lone pairs of electrons on nitrogen (in the case of methylamine) and oxygen (in the case of methoxide), respectively.- Compound 1, an alkene, and Compound 4, an alkyne, while they contain pi bonds, are not strong nucleophiles.Thus, the correct nucleophiles among the given compounds are:- **Compound 2: CH\(_3\)NH\(_2\) (Methylamine)**- **Compound 3: CH\(_3\)O\(^-\) (Methoxide ion)**

Nucleophile is a species which is electron rich. it is having negative charge or lone pair of…

Answered: 3. Which of the following are…

Science

Chemistry

3. Which of the following are nucleophiles? 1 CH3NH2 2 CH ₂0 3 H3CC=CH

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Draw the missing reactant for the following reaction
Answer the question below the reaction. H3C H3C H3C OH H3C In the second step of the reaction mechanism, which of the following is formed? CH3 CH3 CH3 + Excess NH4Cl CH3 CH3 CH3 CH3 H₂SO4 CH3 CI ха +H2O
Draw the structure of the starting material needed to make 2-methylhept-3-yne using sodium amide in liquid ammonia, followed by 1-bromopropane. The starting hydrocarbon must have no more than five carbons 1) NaNH2, NH3() NaBr + 2) CHзCH2CH2Br
H3C CH3 H3C NA C→XT Br Br₂ CH₂Cl₂ H3C Electrophilic addition of bromine, Br₂, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH₂Cl₂. CH3 Br In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product with anti stereochemistry is formed. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions Br CH3 H3C CH3
5A In the following reactions, mixtures of alkenes and ethyl ethers are formed. Draw their structures. Explain which is or are likely to be the main product(s) in each reaction. In case of formation of two isomers of alkenes, explain which is formed in greater proportion CH3 ofi H3C- -Br CH3 EtOH
Draw a structural formula for the major product of the reaction shown. CH₂CH₂CH=CHCH₂CH3Cl₂ H₂O Show product stereochemistry IF the reactant alkene has both carbons of the double bond within a ring. • Do not show stereochemistry in other cases. • If the reaction produces a racemic mixture, just draw one stereoisomer. √ [F* ChemDoodle Next
What is the major substitution product to the following reaction? Br HOCH3 H3CO OCH
Highlight the electrophilic carbon in red, and highlight the leaving group in blue. Highlight the atom in the nucleophile that will attack the electrophilic center in green. Only atoms need to be highlighted and not the lone pairs or formal charges. O O − Cl