3. We will now combine your data with the class in the following table. Total No. No. of Of Pieces Observation Type of (Bag) Observation | Type of Candy Orange No. of Total No. Candy (Bag) BKFHleS CKtles SKitles SKAles 6Kittles BRittles! Clittles 1BKEHles B/ttes BKittles BKittleS EXittles Orange of Pieces MHMC 19 18 3. M+MG 3. M+MS MIMG M-MS MAMA M+MS MIM6 MAMS 21 b. 4. 22 23 6. 24 25 8. 26 9. 18 27 10 28 13 11 12 17 29 30 13 MIMS MIMS 3. SKittles Okities SKHES 31 15 14 15 32 18 13 16 33 17 34 18 35 36 *. Fm in the following contingency table with the number of observations that fall into each com- bination of categories. For example, if there are 100 overall pieces of orange colored Skittles, you would enter 100 into the first cell. Outcome Orange Not Orange (x) Skittles (S) M&M's (M) Candy Row Totals Column Totals 5. Compute the point estimate for the difference in the proportion of orange colored pieces between the two brands.
3. We will now combine your data with the class in the following table. Total No. No. of Of Pieces Observation Type of (Bag) Observation | Type of Candy Orange No. of Total No. Candy (Bag) BKFHleS CKtles SKitles SKAles 6Kittles BRittles! Clittles 1BKEHles B/ttes BKittles BKittleS EXittles Orange of Pieces MHMC 19 18 3. M+MG 3. M+MS MIMG M-MS MAMA M+MS MIM6 MAMS 21 b. 4. 22 23 6. 24 25 8. 26 9. 18 27 10 28 13 11 12 17 29 30 13 MIMS MIMS 3. SKittles Okities SKHES 31 15 14 15 32 18 13 16 33 17 34 18 35 36 *. Fm in the following contingency table with the number of observations that fall into each com- bination of categories. For example, if there are 100 overall pieces of orange colored Skittles, you would enter 100 into the first cell. Outcome Orange Not Orange (x) Skittles (S) M&M's (M) Candy Row Totals Column Totals 5. Compute the point estimate for the difference in the proportion of orange colored pieces between the two brands.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Permutations and Combinations
If there are 5 dishes, they can be relished in any order at a time. In permutation, it should be in a particular order. In combination, the order does not matter. Take 3 letters a, b, and c. The possible ways of pairing any two letters are ab, bc, ac, ba, cb and ca. It is in a particular order. So, this can be called the permutation of a, b, and c. But if the order does not matter then ab is the same as ba. Similarly, bc is the same as cb and ac is the same as ca. Here the list has ab, bc, and ac alone. This can be called the combination of a, b, and c.
Counting Theory
The fundamental counting principle is a rule that is used to count the total number of possible outcomes in a given situation.
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Question
Activity 19 number 4 &5
Transcribed Image Text:3. We will now combine your data with the class in the following table.
Total No.
No. of
Of Pieces
Observation Type of
(Bag)
Observation | Type of
Candy
Orange
No. of
Total No.
Candy
(Bag)
BKFHleS
CKtles
SKitles
SKAles
6Kittles
BRittles!
Clittles
1BKEHles
B/ttes
BKittles
BKittleS
EXittles
Orange
of Pieces
MHMC
19
18
3.
M+MG
3.
M+MS
MIMG
M-MS
MAMA
M+MS
MIM6
MAMS
21
b.
4.
22
23
6.
24
25
8.
26
9.
18
27
10
28
13
11
12
17
29
30
13
MIMS
MIMS
3.
SKittles
Okities
SKHES
31
15
14
15
32
18
13
16
33
17
34
18
35
36
*. Fm in the following contingency table with the number of observations that fall into each com-
bination of categories. For example, if there are 100 overall pieces of orange colored Skittles, you
would enter 100 into the first cell.
Outcome
Orange
Not Orange (x)
Skittles (S)
M&M's (M)
Candy
Row Totals
Column Totals
5. Compute the point estimate for the difference in the proportion of orange colored pieces between
the two brands.
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