3. Using Newton's method, solve for the value(s) of x in the equation below. Use 3 decimal place. e3x² - 4x e-(2x²-4) = 0 Uno 3 decimal place for each iteration.
3. Using Newton's method, solve for the value(s) of x in the equation below. Use 3 decimal place. e3x² - 4x e-(2x²-4) = 0 Uno 3 decimal place for each iteration.
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter5: Exponential And Logarithmic Functions
Section5.2: Applications Of Exponential Functions
Problem 21E
Related questions
Question
answer number 3 write your solution on any peace of paper follow the instructions
![PROBLEM SOLVING. Solve the following problems completely. BOX your final answer.
1. Solve for the value of g and h in the equation below using either Jacobi or Gauss-Seidel iteration. Use 2 decimal places
and initial value of zero.
1.
279 = 9h
81h3-9 = 243
2. Solve the value of a, b and c in the equation below using either Jacobi or Gauss-Seidel iteration. Use 2 decimal places
and initial value of zero.
3a² +6ab + 3ac = 3a
3a² + 5ab + 2b² = a²-b²
a+b+c=2
3. Using Newton's method, solve for the value(s) of x in the equation below. Use 3 decimal place.
e3x²-4x - e-(2x²-4) = 0
4. Use Fixed point iteration, solve for the value(s) of x in the equation below. Use 2 decimal place for each iteration.
f(x) = x³ - 4x -0.5x² + 2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1a304117-5a23-4c05-a2bc-ad1caa4aab79%2Fb284b405-4380-40b9-9d94-0a48ca5c89bf%2Fsdwdrqs_processed.jpeg&w=3840&q=75)
Transcribed Image Text:PROBLEM SOLVING. Solve the following problems completely. BOX your final answer.
1. Solve for the value of g and h in the equation below using either Jacobi or Gauss-Seidel iteration. Use 2 decimal places
and initial value of zero.
1.
279 = 9h
81h3-9 = 243
2. Solve the value of a, b and c in the equation below using either Jacobi or Gauss-Seidel iteration. Use 2 decimal places
and initial value of zero.
3a² +6ab + 3ac = 3a
3a² + 5ab + 2b² = a²-b²
a+b+c=2
3. Using Newton's method, solve for the value(s) of x in the equation below. Use 3 decimal place.
e3x²-4x - e-(2x²-4) = 0
4. Use Fixed point iteration, solve for the value(s) of x in the equation below. Use 2 decimal place for each iteration.
f(x) = x³ - 4x -0.5x² + 2
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