3. Using Newton's method, solve for the e3x²-4x - e-(2x²-4) = 0 4. Use Fixed point iteration, solve for the value(s) of x in the equation below. Use 2 decimal place for each iteration. f(x) = x³-4x -0.5x² +2
3. Using Newton's method, solve for the e3x²-4x - e-(2x²-4) = 0 4. Use Fixed point iteration, solve for the value(s) of x in the equation below. Use 2 decimal place for each iteration. f(x) = x³-4x -0.5x² +2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
answer number 4 write your solution on any peace of paper follow the instructions

Transcribed Image Text:PROBLEM SOLVING. Solve the following problems completely. BOX your final answer.
1. Solve for the value of g and h in the equation below using either Jacobi or Gauss-Seidel iteration. Use 2 decimal places
and initial value of zero.
1.
279 = 9h
81h3-9 = 243
2. Solve the value of a, b and c in the equation below using either Jacobi or Gauss-Seidel iteration. Use 2 decimal places
and initial value of zero.
3a² +6ab + 3ac = 3a
3a² + 5ab + 2b² = a²-b²
a+b+c=2
3. Using Newton's method, solve for the value(s) of x in the equation below. Use 3 decimal place.
e3x²-4x - e-(2x²-4) = 0
4. Use Fixed point iteration, solve for the value(s) of x in the equation below. Use 2 decimal place for each iteration.
f(x) = x³ - 4x -0.5x² + 2
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