3. Using a flow chart, outline a strategy to separate the compounds 1-3 by liquid-liquid extraction usingethyl acetate and an acidic, neutral or basic aqueous solution.Compound 1NH2OHCompound 2HNCompound 3HNOMeagagaOHOYour answer should be a conceptual flowchart (Figure 3-2) to show the steps needed to separate these com-pounds and should include the aqueous solution required for each step and the solubilities of the compounds(i.e., organic or aqueous layer). Also include a brief explanation of how to isolate each pure compound fromsolution after extraction. Your answer should NOT be a detailed procedure as shown below in the "StandardProcedure for a Liquid-liquid Extraction".

Step 1 :Dissolve the mixture of compounds 1-3 in the organic solvent ethyl acetate. Step 2 :Add an…

Answered: 3. Using a flow chart, outline a…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Calculate the pH of two HCl solution based on their concentrations of 0.001 and0.0001 M. Then calculate the pH of a solution when you add each of these to a closed carbonicacid system with mcarb-t = mH2CO3 + mHCO3- + mCO32- = 0.01 m and pH = 6. At that pH, mH2CO3 =10-2.16; mHCO3- =10-2.51; mCO32- is negligible.
PLEASE provide detailed solution...and give the explanation of the correct and incorrect option
At the end of "class", I asked you to consider a triprotic acid with pka's = 2.0, 6.0 and 10.0. What is the equilibrium constant for the reaction H3A + HA²¯ ⇒ 2H₂A? If you need to, assume 25 °C, where Kw = 10-14
Following is the composition of corn oil with common names: myristic 0.1-1.7%, palmitic 8-12%, stearic 2.5-4.5%, oleic 19-49%, linoleic 34-62% Write down the abbreviations of acid using delta approach. Also group them as omega 3, 6, 9 acids.
5. Each mixture below contains 1 mL solvent 1, 1 mL of solvent 2, and 40 mg of the solid. For each, indicate the species contained in each layer using the sketched test tube. Solvent 1 CH,CH,-O-CH,CH, H₂O Solvent 2 CH,CH,-O-CH,CH, H₂O CH₂Cl₂ CH₂Cl₂ H₂O IM HCI (aq) H₂C-N Solid NaCl CH3 H₂C HQ NH₂ Test tube D
For acid-base extractions: Explain what result would you expect if you accidentally extracted the mixture in the reverse order (HCl, NaOH, NaHCO3)? [instead of using NaHCO3 first, NaOH second, and then HCl third]
how do you find mmole of tetraborate and [B4O5(OH)4^2-] for trial 1?
Question 5
You are given the following data: KAHCN = 6.2 x 10-10 Ka HF = 7.2 x 10-4 Ka CH, COOH = 1.8 x 10-5 Ka HOCN = 2.0 x 10-4 %3D Within an aqueous mixture containing 0.42 M CH,COOH and 0.54 M HCN, what are the concentrations of CH3COO and CN? OỊCH,Co0] = 4.4 x 103 M; [CN] = 4.7 x 107 M OỊCH;CO0] = 2.7 x 103 M: [CN] = 1.8 x 10-5 M OỊCH,CO0] = 2.7 x 103 M; [CN] = 1.2 x 107M O None of these answers OỊCH,Co0] = 1.2 x 103 M; [CN] = 2.7 x 107 M
Select one for each box
Which set of conditions will accomplish the transformation shown below? OH OH NaOH in water (solvent), then adjust to solution pH = 6 LIAIH4 in ether (solvent), then dilute aqueous acid H2/ Pd-C in ethanol (solvent) NABH4 in ethanol (solvent)
5 1 X MasteringChemistry erty.edu/webapps/assessment/take/launch.jsp?course_assessment_id%=_1575667_1&course_id%3_592130_1&content_id= 39106439 18 puTube Maps M Gmail YouTube 2 Maps ¥ Question Completion Status: Which is more basic - an aqueous solution of borax or an equivalent concentration aqueous solution of lime water? [H*] (M) pH pOH [OH ] (M) 1 (1x10) 0.0 14.0 1x10-14 Stomach acid 1x10-1 1.0 13.0 1x10 13 Lemon juice Cola, vinegar 1x10-2 2.0 12.0 1x10-12 1x10-3 3.0 11.0 1x10-11 Wine Tomatoes 1x10-4 4.0 10.0 1x10-10 Black coffee 1x10-5 5.0 9.0 1x10-9 Rain Saliva Milk 1×10-6 6.0 8.0 1×10-8 1×10-7 7.0 7.0 1×10-7 Human blood 1×10-8 8.0 6.0 1x10-6 Seawater 1x10-9 9.0 5.0 1x10-5 Borax 1x10-10 10.0 4.0 1x10-4 Lime water 1x10-11 11.0 3.0 1x10-3 Household ammonia Household bleach 1x10-12 12.0 2.0 1x10-2 1x10-13 13.0 1.0 1x10-1 1x10-14 14.0 0.0 1 (1x10) pH + pOH = 14 %3D [H*][OH¯]= 1×10 14 A. borax B. household ammonia C. lime water D. the two solutions will have equivalent pH at…

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