3. Use ANOVA to determine if Student A is the brightest among the 4senior students of XYZ University.Use 1% level of significance.StudentMathEnglishPhysicsSocial Science88908587849482847590838588787596ABCD

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Answered: 3. Use ANOVA to determine if Student A…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A governmental agency computed the proportion of violent crimes in the United States in a particular year falling into each of four olo categories. A simple random sample of 550 violent crimes committed in California during that year were categorized in the same way. The following table presents the results. U.S. California Category Proportion Frequency Murder 0.012 Forcible Rape 0.058 20 Robbery 0.360 207 Aggravated Assault 0.570 318 Send data to Excel Can you conclude that the proportions of crimes in the various categories in California differ from those in the United States as a whole? Use the 0.01 level of significance and the P-value method with the TI-84 Plus calculator. Part: 0 / 4 Part 1 of 4 (a) State the null and alternate hypotheses. Save For Later Submit Assignment Check Answer Skip Part O 2021 McGraw-Hill Education. All Rights Reserved. Terms of Use Privacy (? 5/2 Search insert 山园

Consider a sample with data values of 19,20 , 25, 25,27 , 29 ,30 , and 36. Compute the 20th,25th,65th and 75th percentiles (to 2 decimal, if decimals are necessary). 20th percentile 25thpercentile 65thpercentile 75th percentile
What aspect in statistical process that refers to the extraction relevant information from the acquired data?
A researcher believes there is a difference in the mean number of days before visible results begin to show among three types of facial creams that reduce wrinkle lines. Several consumers are randomly selected and given one of the three creams. Each participant then recorded the number of days it took to see results. The results are shown in the table. Based on these data, can you conclude that there is a difference between the mean number of days for these three creams? Use a 0.05 level of significance and assume the population distributions are approximately normal with equal population variances. Cream #1 20 20 14 17 15 Cream #2 13 15 15 11 13 Cream #3 14 18 15 16 17 10 Copy Data Step 1 of 2: Compute the value of the test statistic. Round any intermediate calculations to at least six decimal places, and round your final answer to four decimal places.
b) If each observation is given by the overall mean + product effect + residual, find the residuals for all above observations and write them in a table. Product effect for each observation is: the group mean - the overall mean So, the product effect is the same for all observations in a group (e.g., A). (Hint: you can use Microsoft Excel, R or SPSS for this)
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 205 Fundash runners and 300 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 205 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.3 minutes. The 300 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.1 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, ,, of Fundash is not equal to the mean completion time, μ₂, of Coolsprint? Perform a two-tailed test.…
Suppose we measure GPA for people in our class, we find the mean is 2.8 and the median is 3.2. What can you say is most likely true about GPAs in our class?
An adventure company runs two obstacle courses, Fundash and Coolsprint. The designer of the courses suspects that the mean completion time of Fundash is not equal to the mean completion time of Coolsprint. To test this, she selects 250 Fundash runners and 285 Coolsprint runners. (Consider these as random samples of the Fundash and Coolspring runners.) The 250 Fundash runners complete the course with a mean time of 76.7 minutes and a standard deviation of 5.7 minutes. The 285 Coolsprint runners complete the course with a mean time of 77.5 minutes and a standard deviation of 5.6 minutes. Assume that the population standard deviations of the completion times can be estimated to be the sample standard deviations, since the samples that are used to compute them are quite large. At the 0.05 level of significance, is there enough evidence to support the claim that the mean completion time, u, of Fundash is not equal to the mean completion time, µa, of Coolsprint? Perform a two-tailed test.…
A researcher gathered a sample of participants who volunteered for a studying of phobias. She measured anxiety level of participants as they viewed photos of spiders and again when they viewed puppies. Which statistical test is appropriate for this study and why?
A researcher wants to know if the news station a person watches is a factor in the amount of time (in minutes) that they watch. The table below shows data that was collected from a survey. Local FOX CNN 44 55 65 46 62 65 32 24 49 22 67 52 23 63 59 38 63 57 26 18 37 38 29 41 The test-statistic for this data = (Please show your answer to 3 decimal places.) The p-value for this sample = (Please show your answer to 4 decimal places.) The p-value is αα Base on this, we should hypothesis As such, the final conclusion is that... There is sufficient evidence to support the claim that station is a factor in the amount of time people watch the news. There is insufficient evidence to support the claim that station is a factor in the amount of time people watch the news.
Investigation 3.2: Valence Differences Between R&B and Rap Genres (Paired)A music fan claims that R&B songs tend to have a more positive tone on average than do Rapsongs. The individual collected two independent random samples from the population of SpotifySongs. Fifteen R&B songs and another fifteen Rap songs were collected and their Valence wasrecorded. The music fan believed that pairing the song by their Danceability may provideadditional information. Danceability describes how suitable a track is for dancing based on acombination of musical elements including tempo, rhythm stability, beat strength, and overallregularity. A value of 0.0 is least danceable and 1 is most danceable. Thus, the individual pairedthe R&B song with the lowest danceability with the Rap song with the lowest danceability,followed by the second and second, third and third. She continued this process until the R&Bsong with the highest danceability was paired with the Rap song with the…
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 75 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. N Mean StDev SE Mean Men Women 95% Cl for mu Men - mu Women - 9.81, - 0.79) T-Test mu Men = mu Women (vs H2 Oc. Họ: H1 = H2; Hai H1

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3. Use ANOVA to determine if Student A is the brightest among the 4senior students of XYZ University. Use 1% level of significance. Student Math English Physics Social Science 88 90 85 87 84 94 82 84 75 90 83 85 88 78 75 96 ABCD