3. Two in phase, monochromatic light rays traverse transparent materials with differing indices of refraction but a common length. The wavelength of the light is 1 =450. nm . Far from the materials the light rays are combined without further phase shifts and there is interference. a. If n, =1.500 n, =1.575 and L=15.0µm what is the phase difference in wavelengths ( N, - N, )? b. If n, =1.425 n, =1.575 and L=15.0µm what is the phase difference in wavelengths ( N, - N,)? c. If n, =1.425 n =1.575 and L=10.5µm what is the phase difference in wavelengths ( N, - N, )? d. Rank the three cases above, a, b, and c, in terms of brightness for the combined light (from brightest to dimmest, use "=" to indicate if two or more are equal in brightness).

icon
Related questions
Question

Please explain parts b, c, and d.

**Interference of Light Rays in Transparent Materials**

Two in-phase, monochromatic light rays traverse transparent materials with differing indices of refraction but a common length. The wavelength of the light is \(\lambda = 450 \text{ nm}\) . Far from the materials, the light rays are combined without further phase shifts and there is interference.

**a.** If \( n_1 = 1.500 \), \( n_2 = 1.575 \) and \( L = 15.0 \mu m \), what is the phase difference in wavelengths \((N_2 - N_1)\)?

**b.** If \( n_1 = 1.425 \), \( n_2 = 1.575 \) and \( L = 15.0 \mu m \), what is the phase difference in wavelengths \((N_2 - N_1)\)?

**c.** If \( n_1 = 1.425 \), \( n_2 = 1.575 \) and \( L = 10.5 \mu m \), what is the phase difference in wavelengths \((N_2 - N_1)\)?

**d.** Rank the three cases above, a, b, and c, in terms of brightness for the combined light (from brightest to dimmest, use “=” to indicate if two or more are equal in brightness).

### Diagram Explanation:
The diagram included in the question shows two light rays (represented by red arrows) traversing two different transparent materials with indices of refraction \(n_1\) and \(n_2\). The length \(L\) is the same for both materials. The materials are shown as two rectangular blocks, with the material having index of refraction \(n_1\) in the yellow region and the material having index of refraction \(n_2\) in the green region.

The light rays eventually recombine after passing through the materials of different refractive indexes leading to interference.

### Calculation and Analysis:
The phase difference in wavelengths \((N_2 - N_1)\) for each case can be calculated using the formula:

\[ \Delta N = \frac{(n_2 - n_1) L}{\lambda} \]

Where: 
- \(\Delta N\) is the phase difference in wavelengths
- \(n_1\) and \(n_2\) are
Transcribed Image Text:**Interference of Light Rays in Transparent Materials** Two in-phase, monochromatic light rays traverse transparent materials with differing indices of refraction but a common length. The wavelength of the light is \(\lambda = 450 \text{ nm}\) . Far from the materials, the light rays are combined without further phase shifts and there is interference. **a.** If \( n_1 = 1.500 \), \( n_2 = 1.575 \) and \( L = 15.0 \mu m \), what is the phase difference in wavelengths \((N_2 - N_1)\)? **b.** If \( n_1 = 1.425 \), \( n_2 = 1.575 \) and \( L = 15.0 \mu m \), what is the phase difference in wavelengths \((N_2 - N_1)\)? **c.** If \( n_1 = 1.425 \), \( n_2 = 1.575 \) and \( L = 10.5 \mu m \), what is the phase difference in wavelengths \((N_2 - N_1)\)? **d.** Rank the three cases above, a, b, and c, in terms of brightness for the combined light (from brightest to dimmest, use “=” to indicate if two or more are equal in brightness). ### Diagram Explanation: The diagram included in the question shows two light rays (represented by red arrows) traversing two different transparent materials with indices of refraction \(n_1\) and \(n_2\). The length \(L\) is the same for both materials. The materials are shown as two rectangular blocks, with the material having index of refraction \(n_1\) in the yellow region and the material having index of refraction \(n_2\) in the green region. The light rays eventually recombine after passing through the materials of different refractive indexes leading to interference. ### Calculation and Analysis: The phase difference in wavelengths \((N_2 - N_1)\) for each case can be calculated using the formula: \[ \Delta N = \frac{(n_2 - n_1) L}{\lambda} \] Where: - \(\Delta N\) is the phase difference in wavelengths - \(n_1\) and \(n_2\) are
Expert Solution
steps

Step by step

Solved in 2 steps with 4 images

Blurred answer