3. The velocity of an object travelling in one dimension is given by the function: v(t) = -3.50t2 + 1.70t – 2 where t is in seconds and v is in m/s. Does the object speed up, slow down, or momentarily stop at t = 2.00 s? Show why/why not.
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![**Problem Statement:**
The velocity of an object traveling in one dimension is given by the function:
\[ v(t) = -3.50t^2 + 1.70t - 2 \]
where \( t \) is in seconds and \( v \) is in m/s.
**Question:**
Does the object speed up, slow down, or momentarily stop at \( t = 2.00 \) s? Show why/why not.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F52cb2a62-9ee6-4078-bc55-c99b068ffd2c%2F09a57e8d-92dd-4718-995b-d8ce2a93e548%2Fgos8eh_processed.jpeg&w=3840&q=75)


Velocity is rate of change of distance . it is measured in m/s.
Velocity of an object travelling in one direction is given by
GIVEN
t=2.00 s
Step by step
Solved in 2 steps









