3. The figure as shown below is a rigid bar which is supported by two rods and a pin support. If the said connections is stress- free, determine the increase or decrease of the temperature in degrees Celsius that will resulted with a tensile stress of 49 mPa for the brass rod. Brass L= 2 m A = 1200 mm? E = 100 GPa C a = 18,7 x 10-6/°C В 3 m 2 m Copper L= 3 m A = 1500 mm? E = 120 GPa a = 16.8 x 10-6/°C Note: Neglect the weight of the bar and assumes that the two rods will subjected to same temperature change

3. The figure as shown below is a rigid bar which is supported by two rods and a pin support. If the said connections is stress- free, determine the increase or decrease of the temperature in degrees Celsius that will resulted with a tensile stress of 49 mPa for the brass rod. Brass L= 2 m A = 1200 mm? E = 100 GPa C a = 18,7 x 10-6/°C В 3 m 2 m Copper L= 3 m A = 1500 mm? E = 120 GPa a = 16.8 x 10-6/°C Note: Neglect the weight of the bar and assumes that the two rods will subjected to same temperature change

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter1: Introduction

Section: Chapter Questions

Problem 1.5.6P: The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular...

See similar textbooks

Similar questions

The shown plate is 60 mm thick and it is made of Magnesium Am1004-T61. The plate is fitted between the rigid frictionless supports as shown and at T, = 20°C it is stress free. Find the stresses in the x and y directions when the temperature increases to T, = 58°C. %3D 150 mm 150 mm Select one: O x: 0 MPa, y: 42.864 MPa Ox: 22.1 MPa, y: 44.2 MPa Ox: 0 MPa, y: 44.2 MPa Ox: 0 MPa, y: 17.8 MPa O x: 13.2 MPa, y: 44.2 MPa Ox: 0 MPa, y: 67.4 MPa 3:10 PM O G 4) ENG 1/31/2021
3) An bronze rod is rigidly attached between a aluminum rod and a steel rod as shown. Axial loads are applied at the positions indicated. Find the maximum allowable value of P that will not exceed a stress in steel of 140MPA, in aluminum of 90MPA or in bronze of 100MPа. Aluminum A = 500mm? Bronze A = 200mm? Steel A = 150mm2 2P ЗР L st = 1.2m L br = 2m Lal = 3.5m
SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and attached to two vertical rods. Assume that the rods were initially stress-free. Allowable stress in steel is 120 MPa and in bronze is 60 MPa. For this problem, a = 1.8m; b = 1.3m; c = 1.7m. b C NANTSELEINE Steel: A = 900 mm² E = 200 GPa L=1.5m Bronze: A=1200 mm² E=83 GPa L=2.0m What is the ratio of the elongation of steel to bronze? O 0.367 O 0.433 O 0.467 0.333
An aluminum tube with the hexagonal cross-section shown is 2.5 ft long and has a constant wall thickness of 0.080 in. Find (a) the largest torque that the tube can carry if the shear stress is limited to 7200 psi. Use G = 4 x 106 psí for aluminum. 11.5 in 0.075 in O 6734 lb-in O 7634 lb-in O 6374 lb-in O 7346 lb-in
3. The rigid bar of negligible weight is pinned at O and attached to two vertical rods. Assuming that the rods were initially stress-free, what is the largest load P that can be applied without exceeding stresses of 150 MPa in the steel rod and 70 MPa in the bronze rod? 2 m -- -1.5 m- 1.5 m 10 Steel A=900 mm2 E=200 GPa L=15 m Bronze A=300 mm2 E= 83 GPa L3D2 m
SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and attached to two vertical rods. Assume that the rods were initially stress-free. Allowable stress in steel is 120 MPa and in bronze is 60 MPa. For this problem, a = 1.8m; b = 1.3m; c= 1.7m. a b C P Steel: A-900 mm² Bronze: A=1200 mm² E = 83 GPa L=2.0 m E = 200 GPa L=1.5m What is the value of P without exceeding the allowable stress of bronze, in kN? O 161 O 174 O 145 124 4
AN ALUMINUM TUBE IS FASTENED BETWEEN A STEEL ROD AND BRONZE ROD AS SHOWN IN THE FIGURE. AXIAL LOADS ARE APPLIED AT THE POSITIONS INDICATED. FIND THE VALUE OF P THAT WILL NOT EXCEED A MAXIMUM OVERALL DEFORMATION OF 5mm OR A STRESS IN THE STEEL OF 120MPa, IN BRONZE OF 130 MPa AND IN ALUMINUM OF 90 MPa. Modulus of Elasticty of Bronze = 80 GPa, Aluminum = 65 GPa and Steel = 210 GPa. 2P P 3P 4P L = 500mm 800 A = 400mm² 900 600 700 C
The rigid bar of negligible weight is supported as shown in the figure. If W = 80 kN, compute the 2 temperature change of the assembly that will cause a tensile stress of 50 MPa in the steel rod. Use the following data: A (in) a (PF) E (GPa) Steel Rod 300 11.7 x 104 200 Bronze Rod 1400 18 x 106 83 Bronze 3 m Steel 1.5 m 1.0 m 2.5 m 1.5 m W
SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and attached to two vertical rods. Assume that the rods were initially stress-free. Allowable stress in steel is 120 MPa and in bronze is 60 MPa. For this problem, a = 1.8m; b = 1.3m; c= 1.7m. b C P Steel: A = 900 mm² Bronze: A=1200 mm² E = 83 GPa L=2.0m E= 200 GPa L = 1.5m What is the value of P without exceeding the allowable stress of steel, in kN? 250 340 280 O230
Q # 4: An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown in Figure. Axial loads are applied at the positions indicated. The value of P is limited to 20 KN in bronze, 72 KN in aluminum and 28 KN in steel Find the area of each section that will not exceed a stress in steel of 280 MPa, in aluminum of 180 MPa, or in bronze of 200 MPa. CLO -2 Steel Aluminum Bronze 2P 4P 2.5 2.0 1.5
The assembly shown in figure below consists of a light rigid bar AB, pinned at O, that is attached to the steel and aluminum rods. In the position shown, bar AB is horizontal and there is a gap, A = 5 mm, between the lower end of the steel rod and its pin support at C. Compute the stress in the aluminum rod when the lower end of the steel rod is touch to its support. A 0.75 m Steel A = 250 mm E = 200 GPa *i* O 1.5 m Aluminum L = 2m A = 300 mm' E = 70 GPa B D
The figure as shown below is a rigid bar which is supported by two rods and a pin support. If the said connections is stress- free, determine the increase or decrease of the temperature in degrees Celsius that will resulted with a tensile stress of EN mPa for the brass rod. Brass L = 2 m A = 1200 mm² E = 100 GPa a = 18.7 x 10-/°C FN=70 B - 3 m - MN=76 2 m Copper L=3 m A = 1500 mm² E = 120 GPa a = 16.8 x 10-/°C SN=50 Note: Neglect the weight of the bar and assumes that the two rods will subjected to same temperature change