Q1 For figures 1 & 2 drawa) D.C load line with Q-point?b) The input & output signals at V₁ = 100mVp.p, (at common Y axis)?Q2 Explain which one from these transistors can be use as amplifier in fig. 3?1. JFET with (IDss = 10mA & VGS off - 2V).==2. D-MOSFET with (IDss = 8mA & VGSoff = -IV).3.E-MOSFET with (K = (6/24)m & VGS th = +2V).Q3 For figure 4 if(V₁ = 40mVpp, IDss= 10mA, Vp = 4v, VGSQ = -2.2 V andIDQ = 2.03 mA).1) Draw A.C equivalent circuit?2) Determine 9m & Vo?3) Calculate Z₁ & Zo?VDDVDD = 10RDVGS(off)=-6IDSS= 5mA1KHHVGS(off) = -5IDSS = 6mA10KV's* 10RD1KVoutRL10KFig.1= 20RG10MVDDRD2KDFr...RGMFig. 310KGRG10MST+12V3.6k2431.lkRL10KFig. 2solve Q3Vou!Fig. 4Vout

Answered: Image /qna-images/answer/4a223a6a-a3df-41c7-8007-56d001d203fe.jpg

3. SPET with (D Q3 For figure 4 if(V₁ = 40mVp.p, IDss= 10mA, Vp = 4v, VGSQ = -2.2 V and IDQ = 2.03 mA). 1) Draw A.C equivalent circuit? 2) Determine 9m & Vo? 3) Calculate Z₁ & Zo? VDD = 10 RD VGS(off)=-6 IDSS= 5mA 1K 10K VGS(off) = -5 IDSS = 6mA 10K V's VDD 10 RD 1K Vout RL 10K Fig.1 RG 10M VDD = 20 RD 2K Fr. RG Fig. 3 G RG 10M S +12V 3.6k 31.1k Vs solve Q3 Vout RL 10K Fig. 2 Vout

3. SPET with (D Q3 For figure 4 if(V₁ = 40mVp.p, IDss= 10mA, Vp = 4v, VGSQ = -2.2 V and IDQ = 2.03 mA). 1) Draw A.C equivalent circuit? 2) Determine 9m & Vo? 3) Calculate Z₁ & Zo? VDD = 10 RD VGS(off)=-6 IDSS= 5mA 1K 10K VGS(off) = -5 IDSS = 6mA 10K V's VDD 10 RD 1K Vout RL 10K Fig.1 RG 10M VDD = 20 RD 2K Fr. RG Fig. 3 G RG 10M S +12V 3.6k 31.1k Vs solve Q3 Vout RL 10K Fig. 2 Vout

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Subject: Electronic s. Please ASAP
a) Determine the output voltage for all input voltages values. b) Sketch the overall output waveform, Vo(t).
In the circuit given in the figure VT = 25mV, | VBE | = 0.7V, R1 = 950.31Kohm, R2 = 22.50Kohm, R3 = 2.51Kohm, R4 = 1.08Kohm, VCC = 13.00V, VEE = 3.00V, VA = 13.08V, Beta Since = 193.00, Rs = 22.94ohm, Ry = 14.49Kohm, calculate the IC current, Ri, R0 and the voltage gain according to the Source (V0 / V1) by making full analysis. When making your transactions, 2 steps will be taken after the point. Select the closest option according to +/- 10% margin of error. There is only one correct answer to the question.
Please solve..
In the circuit given in the figure, Rk = 7.34Kohm, R1 = 1487.50Kohm, R2 = 1845.84Kohm, R3 = 1.61Kohm, R4 = 0.54Kohm, R5 = 19.05ohm, Ry = 91.57Kohm, VCC = 10.00V, VTN = 2.85V, Kn = Since it is 2.44(mA/V^2), C1=10.04uF, C2=13.81uF, C3=14.07UF, calculate the lower cutoff frequency of the circuit in Hz. When making your transactions, 2 digits will be taken after the dot. Write your result in Hz according to + 10% margin of error. While writing the answer, values such as spaces (Hz, KHz) etc. should not be written in front of the value and behind it. Only numeric values should be entered. A period (.) should be used as a decimal separator. An example notation is given below. Let the value you find be 1.15K. You should write 1150.00 in the box. Let the value you find be 432.6. You should write 432.63 in the box. If the correct answer is X, values entered in the range of X ± (X*10/100) (including limits) will be accepted. If x=50, it will be accepted as between [45,55]. VCc R1 R3 C3 VO Q1 Ry…
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In the circuit given in the figure | VBE | = 0.7V, R1 = 11.06Kohm, R2 = 48.24Kohm, RC = 1.03Kohm, RE = 3.09Kohm, VCC = -13.00V, Beta = 150.00, calculate the IC current by full analysis.