3.) Solve the system of simultaneous equations using Gauss-Jordan method 20х — 9х2 + 15х33 354 - 9x1 + 16.x2 - 5x3 = -275 %3D %3D 15х 5х2 + 18х3 — 307 - %3D
3.) Solve the system of simultaneous equations using Gauss-Jordan method 20х — 9х2 + 15х33 354 - 9x1 + 16.x2 - 5x3 = -275 %3D %3D 15х 5х2 + 18х3 — 307 - %3D
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Question
Is there an application to solve this problem? What kind of this software?
![46 . 7:58
Step2
b)
Eliminate the 2nd column
X, X2
b
1
195/239
3189/239
1
35/239
-2314/239
3
1552/239
13968/239
Make the pivot in the 3rd column by dividing the 3rd row by 1552/239
X,
X
by
1.
195/239
3189/239
1
35/239
-2314/239
3
Eliminate the 3rd column
X,
X,
X3
1
-11
3
1
Hide solution
Recalculate
Solution set:
X = 6
X2 = -11
X3 = 9
Computati
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa46353fc-79ba-4d86-a67b-4e7a3d4d3359%2F1e807a8b-7703-4e26-bc0f-7343e3a271ea%2Fn5ea1k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:46 . 7:58
Step2
b)
Eliminate the 2nd column
X, X2
b
1
195/239
3189/239
1
35/239
-2314/239
3
1552/239
13968/239
Make the pivot in the 3rd column by dividing the 3rd row by 1552/239
X,
X
by
1.
195/239
3189/239
1
35/239
-2314/239
3
Eliminate the 3rd column
X,
X,
X3
1
-11
3
1
Hide solution
Recalculate
Solution set:
X = 6
X2 = -11
X3 = 9
Computati
II
![3.)
Solve the system of simultaneous equations using Gauss-Jordan method
20x1 -
9x2 + 15x3
354
— 9х1 + 16х2 -5х3 — — 275
5xз — — 275
%3D
15х — 5х + 18х3
3 307
-](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa46353fc-79ba-4d86-a67b-4e7a3d4d3359%2F1e807a8b-7703-4e26-bc0f-7343e3a271ea%2Fwe9avb8f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3.)
Solve the system of simultaneous equations using Gauss-Jordan method
20x1 -
9x2 + 15x3
354
— 9х1 + 16х2 -5х3 — — 275
5xз — — 275
%3D
15х — 5х + 18х3
3 307
-
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