Use the Laplace transform to solve the given system of differential equations. d?x + x - y = 0 dt? d²y + y - x = 0 dt? x(0) = 0, x'(0) = -3, y(0) = 0, y'(0) = 1 %3D %3D

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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**Educational Content: Solving Differential Equations Using the Laplace Transform**

This example demonstrates how to use the Laplace transform to solve a system of differential equations.

**Given System of Differential Equations:**

1. \(\frac{d^2x}{dt^2} + x - y = 0\)
2. \(\frac{d^2y}{dt^2} + y - x = 0\)

**Initial Conditions:**

- \(x(0) = 0\)
- \(x'(0) = -3\)
- \(y(0) = 0\)
- \(y'(0) = 1\)

**Proposed Solutions:**

- The solution for \(x(t)\) is given as:

  \[
  x(t) = -\frac{1}{3}t - \frac{4}{3\sqrt{3}} \sin(\sqrt{3}t)
  \]

  (Indicated as incorrect by a red cross)

- The solution for \(y(t)\) is given as:

  \[
  y(t) = -\frac{1}{3}t + \frac{4}{3\sqrt{3}} \sin(\sqrt{3}t)
  \]

  (Indicated as incorrect by a red cross)

Each red cross indicates that the proposed solution did not satisfy the system of differential equations or initial conditions.
Transcribed Image Text:**Educational Content: Solving Differential Equations Using the Laplace Transform** This example demonstrates how to use the Laplace transform to solve a system of differential equations. **Given System of Differential Equations:** 1. \(\frac{d^2x}{dt^2} + x - y = 0\) 2. \(\frac{d^2y}{dt^2} + y - x = 0\) **Initial Conditions:** - \(x(0) = 0\) - \(x'(0) = -3\) - \(y(0) = 0\) - \(y'(0) = 1\) **Proposed Solutions:** - The solution for \(x(t)\) is given as: \[ x(t) = -\frac{1}{3}t - \frac{4}{3\sqrt{3}} \sin(\sqrt{3}t) \] (Indicated as incorrect by a red cross) - The solution for \(y(t)\) is given as: \[ y(t) = -\frac{1}{3}t + \frac{4}{3\sqrt{3}} \sin(\sqrt{3}t) \] (Indicated as incorrect by a red cross) Each red cross indicates that the proposed solution did not satisfy the system of differential equations or initial conditions.
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