3. Recall that a Fourier series will converge quickly if the periodic extension of the function is continuous and slowly if it is discontinuous. If the Fourier series converges quickly, we say that it "converges uniformly". Sketch the periodic extensions of the following functions and determine from the continuity whether the Fourier series converges uniformly or not. (Hint: there is no need to calculate any Fourier coefficients.) (a) The periodic extension of f (x) = 1 – x² over the interval [-1, 1] (b) The periodic extension of f(x) = sin(Tx) over the interval [-1/2, 1/2]

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 64E
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3. Recall that a Fourier series will converge quickly if the periodic extension of the function is continuous
and slowly if it is discontinuous. If the Fourier series converges quickly, we say that it "converges uniformly".
Sketch the periodic extensions of the following functions and determine from the continuity whether the
Fourier series converges uniformly or not. (Hint: there is no need to calculate any Fourier coefficients.)
(a) The periodic extension of f (x) = 1 – x² over the interval [-1, 1]
(b) The periodic extension of f(x) = sin(Tx) over the interval [-1/2, 1/2]
Transcribed Image Text:3. Recall that a Fourier series will converge quickly if the periodic extension of the function is continuous and slowly if it is discontinuous. If the Fourier series converges quickly, we say that it "converges uniformly". Sketch the periodic extensions of the following functions and determine from the continuity whether the Fourier series converges uniformly or not. (Hint: there is no need to calculate any Fourier coefficients.) (a) The periodic extension of f (x) = 1 – x² over the interval [-1, 1] (b) The periodic extension of f(x) = sin(Tx) over the interval [-1/2, 1/2]
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