The rig shown consists of a 1200-lb horizontal member ABC and a vertical member DBE welded together at B. The rig isbeing used to raise a 3600-lb crate at a distance x = 11.7 ft from the vertical member DBE. If the tension in the cable is3.4 kips, determine the reaction at E, assuming that the cable is anchored at F as shown in the figure.3.75 ftDA-17.5 ftW = 1200 lb.3600 lbB6.5 ft-EC5 ft10 ftSolution:Create FBD for the system by yourself, take the frame as your FB and detach it from supports:forces and reactions on frame ABCDE.. There aresupports, in total• Identify each force and reactions with their magnitude and directions:1. Weight of the crate Wcrate =lb pointing2. Self weight of the horizontal member ABC WABC3. Reactions on support E: Ex, Ey and ME for a4. Reactions in cable to F:◆ =lb;lb pointingsupport;→ 3. Reactions on support E: Ex, Ey and Me for a4. Reactions in cable to F:• Equilibrium Equations:1.Fx = 0: there are2. F, = 0: there are3. Σ ΜΕ = 0 :kips-ft.→ =✪lb;→ forces in x direction, hence Ex =*Wcrate➜ support;force in y direction, hence Ey =*WABC +*Ex +lb;lb;*Ey + ME +*T= 0, hence M₁ =

Answered: Image /qna-images/answer/4a7f36cb-3461-44ab-912e-3292187cf7cc.jpg

Answered: 3. Reactions on support E: Ex, Ey and…

3. Reactions on support E: Ex, Ey and Me for a 4. Reactions in cable to F: • Equilibrium Equations: 1. Fx = 0: there are FE → = lb; → support; → forces in x direction, hence Ex = lb;

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Laws of Equilibrium

A body is said to be in equilibrium if the system of forces acting on the body tends to keep the body at rest, in other words, there is no translation motion or net torque on the body. Under such conditions, the equilibrium conditions are to be applied to analyze the condition. The branch of mechanics that deals with this condition is known as 'statics'. Under equilibrium, there are no net forces on the body.

Question

The rig shown consists of a 1200-lb horizontal member ABC and a vertical member DBE welded together at B. The rig is
being used to raise a 3600-lb crate at a distance x = 11.7 ft from the vertical member DBE. If the tension in the cable is
3.4 kips, determine the reaction at E, assuming that the cable is anchored at F as shown in the figure.
3.75 ft
D
A
-17.5 ft
W = 1200 lb.
3600 lb
B
6.5 ft-
E
C
5 ft
10 ft
Solution:
Create FBD for the system by yourself, take the frame as your FB and detach it from supports:
forces and reactions on frame ABCDE.
. There are
supports, in total
• Identify each force and reactions with their magnitude and directions:
1. Weight of the crate Wcrate =
lb pointing
2. Self weight of the horizontal member ABC WABC
3. Reactions on support E: Ex, Ey and ME for a
4. Reactions in cable to F:
◆ =
lb;
lb pointing
support;
→

3. Reactions on support E: Ex, Ey and Me for a
4. Reactions in cable to F:
• Equilibrium Equations:
1.
Fx = 0: there are
2. F, = 0: there are
3. Σ ΜΕ = 0 :
kips-ft.
→ =
✪
lb;
→ forces in x direction, hence Ex =
*Wcrate
➜ support;
force in y direction, hence Ey =
*WABC +
*Ex +
lb;
lb;
*Ey + ME +
*T= 0, hence M₁ =

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