3. (Level 1&2) A box is freely moving on a horizontal, frictionless plane when suddenly a slight push changed the motion of the box. At the instant the force is applied the momentum of the box is described by the equation: p = (-3.00kg - m/8)î + (4.00kg - m/s)} The push caused a force to act on the box for quite some time and this force is given by: F = (0.280N/s)tî +(-0.450N/s²)t²j Calculate the momentum of the box after 2 seconds, if the impulse at t = 0 s for both x- and y- components are zero.

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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3. (Level 1&2) A box is freely moving on a horizontal, frictionless plane when suddenly a slight push changed the motion of the box. At the instant the force is applied the momentum of the box is described by the equation:
p = (-3.00kg - m/s)i + (4.00kg - m/s)j
The push caused a force to act on the box for quite some time and this force is given by:
F =
(0.280N/8)tî + (-0.450N /s²)ť° }
Calculate the momentum of the box after 2 seconds, if the impulse at t = 0 s for both x- and y- components are zero.
Transcribed Image Text:3. (Level 1&2) A box is freely moving on a horizontal, frictionless plane when suddenly a slight push changed the motion of the box. At the instant the force is applied the momentum of the box is described by the equation: p = (-3.00kg - m/s)i + (4.00kg - m/s)j The push caused a force to act on the box for quite some time and this force is given by: F = (0.280N/8)tî + (-0.450N /s²)ť° } Calculate the momentum of the box after 2 seconds, if the impulse at t = 0 s for both x- and y- components are zero.
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