3. Given the following grammar: -> -> p I p -> q r -> t |tUse the method discussed in the class to implement a parser which recognizes the sentencesgenerated by this grammar. So the query:s([p,p,q,r,t,t,t],[]).will return true.

Parser : It is a generator which takes a grammar as input , generates source code which can parse…

Answered: 3. Given the following grammar: ->…

Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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Assumptions ... Alphabet = {a, b} • L1 = { a"b" : n ≥ 0 ^ n mod 3 = 0} L2 = {anbm : n ≥ 0 ^ m ≥ 0 ^ n = m −1} To do in this exercise ... ⚫ Find a context-free grammar G such that L(G) = L1 L2, the concatenation of languages L1 and L2. ⚫ Save your context-free grammar as a JFLAP.jff file, and submit that .jff file to Canvas as your solution to th is exercise.
pls anwser in prolog language, thank you.
Consider the following Grammar: <ID> →<ID> <Letter> | <ID> <Digit> | <Letter> <Letter>→ A|B|….|Z|a|b|….|z <Digit>→ 0|1|…….|9 Prove that the given string Ab1x is ambiguous or not
Consider the language consisting of all strings of properly balanced square brackets. The context freegrammar G is defined as follows:1. <Goal> ::= < List >2. <List> ::= < Pair > < List >3. <List> ::= ε4. <Pair> ::= [ <List> ]Note that EOF is the token that immediately follows the start symbol <Goal> and it means end offile (EOF), representing the end of an input sentence. Therefore you can assume FOLLOW{<Goal>} ={EOF}. (a) Give the FIRST sets of <List>, <Goal>, and <Pair>. (b) Give the FOLLOW set of <List>.
Develop a system/application in Prolog that will allow grader to: load a set of student’s grades (see samples from the Table C below) query student’s final letter grade (A, B, C, etc.) by a given student’s name. query student(s) whose grade matches to the input letter grade (e.g., A). For example, show student(s) whose final letter grade is A. There are 3 types of grades for each student—HWs, Exams, and Project, with a weight of 20%, 40% and 40%, respectively, to the 100-point final. Table A and B show how the final grades (in points and letter) are computed. Table C shows samples of students’ grades. You will define the execution instructions to answer the following questions so that grader can test out your application in Prolog: how to load your source code to Prolog runtime/compiler how to load students’ grades to Prolog runtime/compiler how to query student’s letter grade how to query student(s) whose letter grade matches to an input letter grade Please DO NOT hard code any…
I always get the wrong answer for these three, can you please provide me the correct answer for First(S') First(A) (Please see the picture as well)
Can you please help me with this problem because I am struggling big time with this. I only need help with part D can you please show it step by step the context free solution part D. Can you please do it step by step leading up to the solution.Again I only need help with is with part D and only part D.
Give a context free grammar for the set L={a^n b^m | n=m or 2n=m where n, m ≥ 0}.
Consider the context-free grammar S- A$ A→ aAa | B B → bbB | A In each of the following questions list your set in alphabetical order with $ at the end of the list if it's included. Separate items using commas and no spaces. For example: x,y,$. If a set is empty write "empty". What is in First(S)? { What is in First(A)? { } What is in First(B)? { } What is in Follow(S)? { What is in Follow(A)? { } What is in Follow(B)? { }
In using, lists as sets, we wish to judge the list (a b c) and (b c a) as equal because they contain the same elements. Also, we wish to judge sets that contain sets, such as ( a (b c d) e), to be equal to ( e a (c d b)). Implement a scheme predicate called set-equal? that takes as input two lists representing sets and returns true if the lists represent the same set and false otherwise. The difference between this predicate and the one discussed in detail in class is that this predicate will support sets of sets to any degree of nesting, e.g., sets of sets of sets. Thus, the call (set-equal? ‘(a (b (c d))) ‘( ((d c) b) a)))) should return #t and the call (set-equal? ‘(a (b (c d))) ‘( (d c b) a)))) should return #f. Racket code only please. No loops or hash.
Prove this grammar is Ambiguous <S> -> <A> <A> -> <A> + <A> | <id> <id> -> a | b | c

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3. Given the following grammar: -> -> p T p -> q r -> t I t Use the method discussed in the class to implement a parser which recognizes the sentences generated by this grammar. So the query: s([p,p,q,r,t,t,t],[]). will return true.