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3. Given the following data of a closed traverse LINE DISTANCE (m) BEARING 1-2 31.20 N 15°24' E 2-3 28.50 S 82°32' E 3-4 S 33°09' E 4-5 33.00 5-1 24.23 N 65°21' W a. Determine the distance of line 3-4 b. Determine the bearing of line 4-5

3. Given the following data of a closed traverse LINE DISTANCE (m) BEARING 1-2 31.20 N 15°24' E 2-3 28.50 S 82°32' E 3-4 S 33°09' E 4-5 33.00 5-1 24.23 N 65°21' W a. Determine the distance of line 3-4 b. Determine the bearing of line 4-5

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Note: Show how to get the values of the angles’ 3, 4, and 5 by using the sine law and by adding (refer on sample problem 2).
3. Given the following data of a closed traverse LINE DISTANCE (m) BEARING 1-2 31.20 N 15°24' E 2-3 28.50 S 82°32' E 3-4 S 33°09' E 4-5 33.00 5-1 24.23 N 65°21' W a. Determine the distance of line 3-4 b. Determine the bearing of line 4-5
Transcribed Image Text:3. Given the following data of a closed traverse LINE DISTANCE (m) BEARING 1-2 31.20 N 15°24' E 2-3 28.50 S 82°32' E 3-4 S 33°09' E 4-5 33.00 5-1 24.23 N 65°21' W a. Determine the distance of line 3-4 b. Determine the bearing of line 4-5
Sample Problem 2 A 1,738.96m E LATITUDES DEPARTURES LINE LENGTH BEARING +N -S +E /14°01' 1084.32 m S 75°48' E S 15'18' W AB -265.9917 1051.1890 28°39 ВС 1590.51 1534.1382 419.6927 S 68*06' W Unknown N 28 39' W CD 1294.74 482.9222 -1201.3067 42°40' DE 28°39' + 14°01' EA 1738.96 Unknown SUMS 2,283.0521 1,051.1890 1,620.9994 Σεο WD D Determining Length of Line DE and Bearing of Line EA: Sum of Interior Angles for Triangle = 180° ZA = 180° - (42°40' + 66°30') ZA = 70°50' ZD = 28°39' + 14°01' ZD = 42°40' By Sine Law: DE EA At Station E: e = 180° - (ZE + 28°39') e = N 84°51' E [Bearing of Side EA] By Sine Law: sin A DE = sin D DA E A [1,738.96m][sin(70°50')] sin(42°40') DE = 2,423.6205m sin E sin D sin E [2,353.0854m][sin(42°40')] %3D 1,738.96m ZE = 66°30' [Length of Side DE] 2,353.0854m
Transcribed Image Text:Sample Problem 2 A 1,738.96m E LATITUDES DEPARTURES LINE LENGTH BEARING +N -S +E /14°01' 1084.32 m S 75°48' E S 15'18' W AB -265.9917 1051.1890 28°39 ВС 1590.51 1534.1382 419.6927 S 68*06' W Unknown N 28 39' W CD 1294.74 482.9222 -1201.3067 42°40' DE 28°39' + 14°01' EA 1738.96 Unknown SUMS 2,283.0521 1,051.1890 1,620.9994 Σεο WD D Determining Length of Line DE and Bearing of Line EA: Sum of Interior Angles for Triangle = 180° ZA = 180° - (42°40' + 66°30') ZA = 70°50' ZD = 28°39' + 14°01' ZD = 42°40' By Sine Law: DE EA At Station E: e = 180° - (ZE + 28°39') e = N 84°51' E [Bearing of Side EA] By Sine Law: sin A DE = sin D DA E A [1,738.96m][sin(70°50')] sin(42°40') DE = 2,423.6205m sin E sin D sin E [2,353.0854m][sin(42°40')] %3D 1,738.96m ZE = 66°30' [Length of Side DE] 2,353.0854m
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