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3. Find the points of discontinuity and describe the type of discontinuity at each point. f(x) = x-1 x(x-1)(x+2)

3. Find the points of discontinuity and describe the type of discontinuity at each point. f(x) = x-1 x(x-1)(x+2)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Can you please help with a step by step of how to solve problem 3?
(2x + 4 x ≥2) x= f(2)= (2)³ = 8 f(2)= 2 (2) + 4 = 8 Continuous 3. Find the points of discontinuity and describe the type of discontinuity at each point. x-1 f(x) = x(x-1)(x+2) f(x) = {a√x- a 4. Find the value of that makes the function continuous. {a√x + 1 x ≥ 1} 2x - a x < 1)
Transcribed Image Text:(2x + 4 x ≥2) x= f(2)= (2)³ = 8 f(2)= 2 (2) + 4 = 8 Continuous 3. Find the points of discontinuity and describe the type of discontinuity at each point. x-1 f(x) = x(x-1)(x+2) f(x) = {a√x- a 4. Find the value of that makes the function continuous. {a√x + 1 x ≥ 1} 2x - a x < 1)
Expert Solution
Step 1

Given that

                 f(x) = (x - 1)/(x(x - 1)(x + 2))

denominator is x(x-1)(x+2) that is zero at x =0,1,-2

:: f(x) is discontinuous at x = 0 1, -2 because it is not even defined there.

 

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