3. Find the equation of a curve for which y" = 6x - 4 and which passes through (1,2) and (-2 ,5). 4. If f'(x)= 12x² + 6x – 4, f(0) = 4 and f(1) = 1, find f(x). f(x) = x* + x³ - 2x² – 3x + 4 Ans. y=x'- 2x² – 6x +9 %3D Ans %3D

3. Find the equation of a curve for which y" = 6x - 4 and which passes through (1,2) and (-2 ,5). 4. If f'(x)= 12x² + 6x – 4, f(0) = 4 and f(1) = 1, find f(x). f(x) = x* + x³ - 2x² – 3x + 4 Ans. y=x'- 2x² – 6x +9 %3D Ans %3D

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter7: Integration

Section7.1: Antiderivatives

Problem 7YT: YOUR TURN Find an equation of the curve whose tangent line has slope f(x)=3x1/2+4 and passes through...

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Question

Can anyone please help me with the solution for problems 3&4 the answer is already provided

3. Find the equation of a curve for which y" = 6x-4 and which passes
through (1,2) and (-2 ,5).
4. If f'(x) = 12x² + 6x – 4, f(0) = 4 and f(1) = 1, find f(x).
f(x) = x4 + x³ - 2x² – 3x +4
Ans. y x - 2x² – 6x +9
Ans
%3D

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