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3. Find the equation of a curve for which y" = 6x - 4 and which passes through (1,2) and (-2 ,5). 4. If f'(x)= 12x² + 6x – 4, f(0) = 4 and f(1) = 1, find f(x). f(x) = x* + x³ - 2x² – 3x + 4 Ans. y=x'- 2x² – 6x +9 %3D Ans %3D

3. Find the equation of a curve for which y" = 6x - 4 and which passes through (1,2) and (-2 ,5). 4. If f'(x)= 12x² + 6x – 4, f(0) = 4 and f(1) = 1, find f(x). f(x) = x* + x³ - 2x² – 3x + 4 Ans. y=x'- 2x² – 6x +9 %3D Ans %3D

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Can anyone please help me with the solution for problems 3&4 the answer is already provided
3. Find the equation of a curve for which y" = 6x-4 and which passes through (1,2) and (-2 ,5). 4. If f'(x) = 12x² + 6x – 4, f(0) = 4 and f(1) = 1, find f(x). f(x) = x4 + x³ - 2x² – 3x +4 Ans. y x - 2x² – 6x +9 Ans %3D
Transcribed Image Text:3. Find the equation of a curve for which y" = 6x-4 and which passes through (1,2) and (-2 ,5). 4. If f'(x) = 12x² + 6x – 4, f(0) = 4 and f(1) = 1, find f(x). f(x) = x4 + x³ - 2x² – 3x +4 Ans. y x - 2x² – 6x +9 Ans %3D
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