Two students, James and Joe were solving the equation 6-5(11-2x) = 17x. Their work is shown below for questions 2 - 5. James' Work 6-5(11-2x) = 18x 6-5(11-2x) =18x 6 6 -5(11-2x) = 3x -55+ 10x = 3x -10x10x -55 = -7x -7 -7 7 9/3 = x Joe's Work 6-5(11-2x) = 17x 6-55+ 10x = 17x -49 + 10x = 17x -10x10x -49 = -7x -7 -7 7=x students used in solving the equation.

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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Two students, James and Joe were solving the equation 6-5(11-2x) = 17x. Their work
is shown below for questions 2 - 5.
James' Work
6-5(11-2x) = 18x
6-5(11-2x) =18x
6
6
-5(11-2x) = 3x
-55 + 10x = 3x
-10x10x
-55 = -7x
-7 -7
7 = = x
J:SC
Joe's Work
6-5(11-2x) = 17x
6-55 +10x = 17x
-49 + 10x = 17x
-10x10x
:
-49 = -7x
-7 -7
7=x
first stop the students used in solving the equation.
Transcribed Image Text:Two students, James and Joe were solving the equation 6-5(11-2x) = 17x. Their work is shown below for questions 2 - 5. James' Work 6-5(11-2x) = 18x 6-5(11-2x) =18x 6 6 -5(11-2x) = 3x -55 + 10x = 3x -10x10x -55 = -7x -7 -7 7 = = x J:SC Joe's Work 6-5(11-2x) = 17x 6-55 +10x = 17x -49 + 10x = 17x -10x10x : -49 = -7x -7 -7 7=x first stop the students used in solving the equation.
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