3. Find out the MIPS instructions for the following code:A = B - X[4];If(A >= C){C= 800;D = 50000; // 50000 = 0XC350}elselD = C+ 7000000; / 7000000 = 0X6ACFCO}X[8] = D - 400;%3DAssume the address of first instruction is 2000 in decimal. The program/saved registers andtemporary registers are available as $s0 -- $s7 and $t0 - $t9 respectively.

SUMMARY: - hence, we got the desired output.

Answered: 3. Find out the MIPS instructions for…

3. Find out the MIPS instructions for the following code: A = B - X[4]; If(A >= C){ C - 800; D = 50000; // 50000 = OXC350

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Q: Task: Convert the character in AL to upper case.

A: GIVEN: Convert the character in AI to uppercase.

Q: This is Computer Architecture! Instructions: Create a MIPS program that demonstrates that the…

A: Algorithm:Start.Load single-precision floating-point constants into registers.Compute the result of…

Q: Q2- The sum of a 100 * 100 matrix (total 10000 number) of floating point numbers is calculated usin…

A: Ans - here we have a matrix of 100x100 means 10000 number in a matrix so sum of all the number is…

Q: Given n, the number of input register bits in decimal form, two primes p and q, and a number b,…

A: C++ Code: #include<iostream>#include<math.h>#include<vector>using namespace…

Q: [+] 100 the hexadecimal code for the following program (hand-assemble it) Load A 101 Add One 102…

Q: Q7. are 0, 0, 1, and 0, respectively. Find the value of the N, Z, C, V flags of the following…

Q: 420-424 in your text. The program is to request the user to enter a 12-bit Hamming code and…

A: ECC Hamming codes are explained on pages 420-424 in your text. The program is to request the user…

Q: 2) Generate the three address code for the following program segment and apply code optimization to…

A: Task : Given the sample code. The task is to convert to three address codes.

Q: int i, j, k; int suma 0; %3D for (j = 1; j = j; -i) suma += i + j;

A: Given code, int i,j,k int sum=0; for(j=1;j<=k;++j) for(i=k;i>=j;--i) sum+=i+j; We…

Q: Convert the following C code to MIPS assembly code. if (a>0 && a<20) { a++;

A: if (a > 0 && a < 20){ a++;} Pseudocode: The above code can be rewritten as if (a…

Q: ing program using LOOP instruction: MOV AL,X MOV BL,X INC DL ADD AL,X INC DL ADD AL,X INC DL…

A: using emu8086: Rewrite the following program using LOOP instruction: MOV AL,X MOV BL,X INC DL ADD…

Q: MIPS ONLY

A: main: push rbp mov rbp, rsp sub rsp, 16 mov DWORD PTR…

Q: What is the single MIPS instruction, or if not possible, the shortest sequence of MIPS instructions…

A: The benefits of the variable-length instruction in computer architecture are:- • The first benefits…

Q: for (i=0; i<1000; i++){ y[i] = w * x[i] + b[i]; } Above C-code has a for loop which will repeat…

A: Introduction for (i=0; i<1000; i++){ y[i] = w * x[i] + b[i]; } Above C-code has a for loop which…

Q: Q1. i) Explain each of following instructions: (a) MOV R5,R3,RO (b) MOV RO,#x56 (c) LDR…

A: Answer is given below

Q: Convert the C function below to MIPS assembly language. Make sure you follow the MIPS calling…

A: The program here is the recursive function if the addition of first 'n' natural numbers. So instead…

Q: use SSE instructions to add 12 floating point numbers. int main(int c, char** s) { float ary[] =…

A: SSE instructions are an extension of the SIMD execution model introduced in MMX technology. SSE…

Q: The Fibonacci equation can be given as: F = F2 1 and the recurrence is Fn = Fn-1+ Fn-2 %3D %3D п-1…

A: Answer: #include<stdio.h> #include<conio.h> int main() //execution starts from here {…

Q: 2 Implement the following operation using arithmetic operation. 8 (AX) - 5 (BX) - (BX) /3 (AX)

A: Here, we have to write the code for the given arithmetic operation: 8(AX)-5(BX)-(BX)/3 -> (AX)

Q: Using the following C code and assembly code answer the following; C: long int…

A: C, known for its simplicity and power, is the most widely used programming language.In particular,…

Q: 26. Find the time delay in the following program if the crystal frequency is 1 MHz. Do not ignore…

Q: CODE HAS TO BE IN EMU 8086 ASSEMBLY LANGUAGE Write a program to find the maximum number and the…

A: org 0x0100 ;srarting position Arrayd: dw…

Q: PROBLEM 21 - 0510: Write a PL/I procedure that reads an integer N > 1 and calculates the sequence Y…

A: We will set up a DO loop to calculate the terms as indicated by the summation symbol, (∑). Program…

Q: In the instruction cycle, the operation during time T1 is: O A. AR PC O B. IR -M[AR], PC PC + 1 O c.…

A: initially, the program counter PC is loaded with the address of the first instruction in the…

Q: Arduino programing, please explain. What is the final value of y after this code is executed?…

A: 0b_____ meaning binary0x_____ meaning hexa unsigned char y = 0b01010000; unsigned char *p = &y;…

Q: Convert the following C code to native hardware MIPS assembly. The variables a, b and x are signed…

A: sge Rdest, $s0, $s1 # if (a >= b), if a>=b, it stores value 1 in Rdest beq Rdest, $0,…

Q: Add number O×3D FE 18 4D 92 3E AA 63 to register x4 using only real instructions.

A: Fork call is employed for making a replacement method, that is named kid method, that runs at the…

Q: Please change this C code to Assembly program(x86 and ARM assembly gcc) #include int main() {…

A: We have a C language program to find prime numbers to a range. We need to convert this C language…

Q: Ex2) Translate the following C code into RISC-U instruction & B[4]=C-A[5] X6 (7) XII XIO (5)

A: Here we have given translated code from C to RISC-V. You can find the solution in step 2.

Q: OpenMP C++ With the following code, create 3 versions: Outer loop parallelism: use a single OpenMP…

A: Outer loop parallelism: use a single OpenMP pragma only at the outer loop Sparse-matrix-vector-…

Q: Give MIPS instructions for this code: N=M- 4*(A[3]-B[2]-6)

A: The answer is

Q: Microprocessor (AVR) Fundamentals 1) - Find the contents of register R20 after each of the following…

A: As per policy three subparts can be solved once.

Q: Write a program segment to poll for ADC14MEM6 and load the result to register r7. (Hint pase address…

A: MOV.W ADC14MEM6, r7 The corresponding bit of the ADC14IFGRO register will be set to 1 after the…

Q: // Example 8.27a void Func(int a[], int & r) { int i; for (i = 0; i < 100; i++) { a[i] = r + i/2;…

A: The solution is given below for the above given question:

Q: W rite a MIPS program to continuously generate the following series of integers: 1, 2, 3, 6, 9, 18,…

A: In this MIPS program, we will generate a series of integers, beginning with 1 and doubling the…

Q: 13. Given the following Java loop, write the equivalent MIPS instructions. for (int i = 5; i < 75; i…

A: #working code li $t0, 75 #t0 is constant 75 li $t1, 5 #t1 is…

Q: Write the sequence of micro-operations for each cycles required to execute the instruction JB R1,…

A: Task : Implement subtraction using two's complement method.

Concept explainers

Computer Fundamentals

The computer is termed computation. For calculating or computing something the device that has been used is known as the computer. Or we can say that for performing a fast arithmetic operation the device that has been used is a computer. Storing, processing, and retrieving are the main features of a computer. 

Question

3. Find out the MIPS instructions for the following code:
A = B - X[4];
If(A >= C){
C= 800;
D = 50000; // 50000 = 0XC350
}
elsel
D = C+ 7000000; / 7000000 = 0X6ACFCO
}
X[8] = D - 400;
%3D
Assume the address of first instruction is 2000 in decimal. The program/saved registers and
temporary registers are available as $s0 -- $s7 and $t0 - $t9 respectively.

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions

Generate MIPS code for the following code segments assuming that all variables are in memory locations.
LIST P = 16F877AUsing INCLUDE "P16F877A.INC" and PWM (Pulse Width Modulation), write the microprocessor code that enables the fan to operate at 80% if the button on the 5th bit is pressed, and 30% if the button on the third bit is pressed.
Translate the following MIPS code to C. Assume that the variables f, g, h, i, and jare assigned to registers $s0, $s1, $s2, $s3, and $s4, respectively. Assume that the baseaddress of the arrays A and B are in registers $s6 and $s7, respectively and that A and B are arrays of words. addi $t0, $s6, 4lw $t0, 0($t0)add $t0, $t0, $t0sw $t0, 0($s6)
Using the following C code and assembly code answer the following; C: long int nothingGreater(long int num) { if (num > 240) { return 240 - num; } else { return num; } } Assembly: 0x00000000004004ed <+0>: push %rbp 0x00000000004004ee <+1>: mov %rsp,%rbp 0x00000000004004f1 <+4>: mov %rdi,-0x8(%rbp) 0x00000000004004f5 <+8>: cmpq $0xf0,-0x8(%rbp) 0x00000000004004fd <+16>: jle 0x40050a <nothingGreater+29> 0x00000000004004ff <+18>: mov $0xf0,%eax 0x0000000000400504 <+23>: sub -0x8(%rbp),%rax 0x0000000000400508 <+27>: jmp 0x40050e <nothingGreater+33> 0x000000000040050a <+29>: mov -0x8(%rbp),%rax 0x000000000040050e <+33>: pop %rbp 0x000000000040050f <+34>: retq The instruction mov $0xf0,%eax at address 0x4004ff puts a value into register %eax but there are no other references to %eax in the program. Which instruction makes use of this value? What is the address of the instruction (0x-prefixed hex)? What…
Write the three-address code for the following program snippet: While p < q If r < s Then Else End If End While a = (b + c) *k a = (b - c) * k
Please show all steps, Thank You!
Please change this C code to Assembly program(x86 and ARM assembly gcc) #include <stdio.h>int main() { unsigned guess; /* current guess for prime */ unsigned factor; /* possible factor of guess */ unsigned limit; /* find primes up to this value */ printf("Find primes up to: "); scanf("%u", &limit); printf("2\n"); /* treat first two primes as special case */ printf("3\n"); guess = 5; /* initial guess */ while ( guess <= limit ) { /* look for a factor of guess */ factor = 3; while ( factor*factor < guess && guess % factor != 0 ) factor += 2;if ( guess % factor != 0 ) printf("%d\n", guess); guess += 2; /* only look at odd numbers */ }printf("Recieves a number(limit) and prints its all divisors"); for(int i = 1; i <= limit; i++) { if((limit%i) == 0){ printf("\n%d", i); } } return 0; }
Part II - Program Instructions for Coding problem. Write a MARIE assembly program to do the following Computer Science The user input 10 numbers: 10 20 30 40 50 60 70 80 90 100 * Write a routine thatReads in 10 integers and uses the 10 integers to calculate the AVERAGE, MINIMUM and MAXIMUM, and STANDARD Deviation for the integers. * Print out the values of avg, min, max and Standard Deviation.
Write down the MIPS code for the following C code: Int task02 (int x, int y) { х х + у; if (x < 25) { z = x - y; else { z = y - x; } return z; } Here 25 is a constant integer value. Use $s0 for z.
What is the execution result for each of the following instructions : - 1. LHLD 3003 ( [3OO2]=9OH,[30O4]=99H , [3OO1]=1OH,[3OO3]=43H)2.CMA ( If A= 9H ) 3. ADI A, 15H ( A=O1H) 4. INB (If B=34 H) 5. LXI * H 50 H
1)Write the following code segment in MARIE assembly and test it. int x, y; scanf(“%d”, &x); If ( x > 1) { y = x + x; x = 0; } y = y + 1; printf(“%d”, y); exit(0);
verify answers please Fill in the following table with the correct answers. Show all values in hexadecimal. Initial Value OF value in Final value Instruction in %al (hex) (hex) (0 or 1) %cl in %ax (hex) 1. imulb %cl Ox83 Ox25 12ef 2. imulb %cl Ox56 Ох6F 254a 1. 3. imulb %cl OxF OXFA ffa6 4. imulb %cl Ox76 Ox74 3578 5. imulb %cl OXE6 OXFE fe 6. imulb %cl Ox27 OXFD ff8b