ALLO>3. Extract a FieldYour program is receiving records from the network, formatted as described in the table below:Bytes0-34-78-1112-15***0Bits 7 6 5 4 3 2(record[2] & 0xF0) >> 4(record[6] | OXF) >> 4(record[2] >> 4) & 0x7(record[2] & 0x7) << 110 765destination-id(record[6] & 0x70) >> 4Clear Selectionsource-id1243210 7 6 5 4 3sizedataflag210 7 6 5message-typeThe records are provided as byte arrays (or lists) such that the 'destination-id' field, for example, is contained in record [4] and record [5]. How would you go about extracting out the 'flag' field and returning its value?Pick ONE optionpri4332 1 0data-routing(Alt + A)

Bitwise operations involve manipulating individual bits in a binary representation of data.…

Answered: 3. Extract a Field Your program is…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Here function f returns the results through address passing. Assuming c is a global complex number defined in main.c, please implement f.h by selecting line numbers from the following lines in correct order. Remember each blank can hold just one line number. 1 #include 2 #include 3 #include "g.h" 4 #include "f.h" 5 extern c_t c; 6 c tc; 7 c_t g(c_t, c_t): 8 c_t g(c_t a, c_t b){ 9 c_tre, 10 c_t re1, re2; 11 else { f(&re1, n-1); f(&re2, n-2); *re = g(re1, re2); } 12 f.o: f.h g.h 13 f(&re, 10); 14 f: main.o f.o g.o дсс -c f.c gcc -c g.c gcc -c main.c gcc -o f main.o f.o g.o -Im 15 16 17 18 19 g.o: g.h 20 if (n <= 1) *re = c; 21 int main(void) 22 main.o: f.h g.h 23 printf("%f\n", sqrt(re.x - re.y)); 24. rox 24 re.x = a.x"b.x - a.y*b.y; 25 re.y = a.x*b.y + b.x*a.y; 26 return 1- 27 return re: 13; 28 scanf("%lf%lf", &c.x, &c.y): 29 typedef struct { double x, y; } c_t; 30 void f(c_t *, int); 31 void f(c_t *re, int n) { 32 }
4. Write a program to implement the address book using dynamic singly linked list, the node should contain name, address and phone#: (1) Write a function create to store three people's information into the singly linked list; (2) Write a function print to print these information to the standard output; (3) Write a function search to find the telephone number of a contact input by name. CA "C:\Documents and Settings\Administrator á Lab\2\Debug\final.2.exe" ******************* Input ******************* Input name: Zhang San Input address: XUPT Input phone: 123456 Input name: Li Si Input address: XJTU Input phone: 789012 Input name: Wang Wu Input address: Clemson Input phone: 345678 ******************* andano ******************** Name: Zhang San Address: XUPT Phone: 123456 Name : Li Si Address: XJTU Phone: 789012 Name: Wang Wu Address: Clemson Phone: 345678 Please input the name to search: Li Si Contact Li Si: phone number is 789012 Press any key to continue.
lices Font Peragrsoh Diraving Example: • Move a block of N consecutive bytes of data starting at offset address BIK1ADDR in memory to another block of memory locations starting at address Blk2ADDR. Assume that both blocks are in the same data segment whose starting point is defined by the data segment value DATASEGADDR. 11 Steter
Create a program in C++ which simulates a direct cache. The memory array that contains the data to be cached is byte addressable and can contain 256 single byte entries or lines. The cache has only 8 entries or lines. The Data field in each line of the cache is 8 bits. Since the data stored in each line of the cache is only 8 bits, there is no need for a line field. Only a tag field is needed which is log2(256) = 8 bits. The memory array can be filled with any values of your choice. The program should work by taking user input of a memory address (index). This input represents the memory data that should be cached. Your program will check the cache to see if the item is already cached. If it is not, your program should count a cache miss, and then replace the item currently in the cache with the data from the inputted address. Allow the user to input addresses (in a loop), until they so choose to end the program. The program should output the number of cache misses upon ending.
IN JAVA SCRIPT Create a function that takes an integer n and reverses it. Examples rev (5121) ➡ "1215" rev (69) ➡ "96" rev (-122157) "751221" (Ctrl)
The array sum function below is called on an array of length four starting at address B. List, in order, the data addresses referenced by this function during execution. add1: add $v0, $0, $0beq1: beq $a1, $0, jr1addi1: addiu $a1, $a1, -1lw1: lw $t0, 0($a0)add2: add $v0, $v0, $t0addi2: addiu $a0, $a0, 4beq2: beq $0, $0, beq1jr1: jr $ra
array([[ 1960, 54211], [ 1961, 55438], [ 1962, 56225], [ 1963, 56695], [ 1964, 57032], [ 1965, 57360], [ 1966, 57715], [ 1967, 58055], [ 1968, 58386], [ 1969, 58726], [ 1970, 59063], [ 1971, 59440], [ 1972, 59840], [ 1973, 60243], [ 1974, 60528], [ 1975, 60657], [ 1976, 60586], [ 1977, 60366], [ 1978, 60103], [ 1979, 59980], [ 1980, 60096], [ 1981, 60567], [ 1982, 61345], [ 1983, 62201], [ 1984, 62836], [ 1985, 63026], [ 1986, 62644], [ 1987, 61833], [ 1988, 61079], [ 1989, 61032], [ 1990, 62149], [ 1991, 64622], [ 1992, 68235], [ 1993, 72504], [ 1994, 76700], [ 1995, 80324], [ 1996, 83200], [ 1997, 85451], [ 1998, 87277], [ 1999, 89005], [ 2000, 90853], [ 2001, 92898], [ 2002, 94992], [ 2003, 97017], [ 2004, 98737], [ 2005, 100031], [ 2006, 100832], [ 2007, 101220], [ 2008, 101353], [ 2009, 101453], [ 2010, 101669], [ 2011, 102053], [ 2012, 102577], [ 2013, 103187], [ 2014, 103795], [ 2015, 104341], [ 2016, 104822], [ 2017, 105264]]) Question 2 Now that we have have our…
convert the following code to MIPS
Computer Science Write a C program that calls malloc() 1001 times allocating blocks of size 4 each. Use type char * to store the pointers returned by malloc(). When done, print the difference in the addresses of the first and last block allocated. This difference is the amount of memory malloc actually used to create 1000 blocks of size 4. It is a lot more than you would expect. Repeat this for other block sizes and make a table of your results. Do you see any pattern? Any guesses why?
Assume variables have logical addresses with 16-bit page numbers and 16-bit offset using the memory configuration below. (Note that each hexidecimal is 4 bits long and Ox means hexadecimal radix) Logical Address Format Physical Memory Physical Address (starting) Page Table Oxppppdddd Page | Frame Frame Size (hex) Size (dec) Ox10000 Ox10000 2 Охс000 65536 pppp: page number dddd: page offset 1 1 Oxd000 65536 2 2 Oxe000 Ox10000 65536 3 Oxf000 Ox10000 65536 Translate the following addresses: What is the physical address for 0x0000ee00 ? What is the physical address for Ox00020001 ? What is the logical address for Oxe0001234 ? What is the logical address for Oxc0004268 ?
2. [summary_report.py] Timesheet data is easy to represent in a file, where it can be used to generate a report and help the worker get paid! Given an example set of data where each row represents a day of the week and each entry on the row represents a block of time worked, like this: 1.5h 3.25h 3.8h 6.Oh 1.eh 5. 5h 2.25h 0.75h 2.25h 3.0h 3.0h 5.75h 2.25h A report could be produced by a program like this: 0.00h | 5.25h | 1.5en 3.25h 0.5eh 10.00h 0.00h 3.00h 6.00h 1.00h 8.50h 5.50h 2.25h 8.75h 8.25h 8.00h 0.00h | e.00h 2.25h 3.00h 3.00h 5.75h 2.25h Weekly Total: 40.00h Notice how in the output file all the numbers are nicely formatted as right-aligned. Hint: you will probably need to use splitting, string slicing, converting data types, and string formatting. create a program that uses a data file that you have created, parses the data in that file to create a calculation per row and a running total, then writes the report to an output file. Your program should prompt a user to input a…
Language: Python i have a txt named "hightemp.txt" I want to sort the rows from highest to lowest in the third column please help me , thanks Here is the content of "hightemp.txt" A AA 41 2013-08-12B BB 40.9 2007-08-16C CC 40.9 2007-08-16D DD 40.8 1933-07-25E EE 40.7 2013-08-10F FF 40.6 1994-08-08G GG 40.6 1994-08-04H HH 40.5 2013-08-10 Q QQ 40 2007-08-16R RR 40 2001-07-24S SS 39.9 2013-08-11T TT 39.9 1997-07-05U UU 39.9 1994-08-08V VV 39.9 1990-07-19W WW 39.9 1978-08-03I II 40.4 2007-08-16J JJ 40.3 2007-08-16K KK 40.3 1998-07-04L LL 40.3 1994-08-05M MM 40.2 2004-07-20N NN 40.2 2001-07-24O OO 40.2 1927-07-22P PP 40.1 1978-08-03X XX 39.9 1942-08-02

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