ALLO>3. Extract a FieldYour program is receiving records from the network, formatted as described in the table below:Bytes0-34-78-1112-15***0Bits 7 6 5 4 3 2(record[2] & 0xF0) >> 4(record[6] | OXF) >> 4(record[2] >> 4) & 0x7(record[2] & 0x7) << 110 765destination-id(record[6] & 0x70) >> 4Clear Selectionsource-id1243210 7 6 5 4 3sizedataflag210 7 6 5message-typeThe records are provided as byte arrays (or lists) such that the 'destination-id' field, for example, is contained in record [4] and record [5]. How would you go about extracting out the 'flag' field and returning its value?Pick ONE optionpri4332 1 0data-routing(Alt + A)

Bitwise operations involve manipulating individual bits in a binary representation of data.…

Answered: 3. Extract a Field Your program is…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

Write in C sharp programming Write a program that encodes and decodes a string using given encryption key (cipher). The key consists of a sequence of characters. The encoding/decoding is done by performing XOR (exclusive or) operation over the first letter of the string with the first of the key, the second – with the second, etc. When the last key character is reached, the next is the first.
code required in mips programming language a .s or .asm code not a c code. Write a MIPS procedure that takes as its two parameters the starting address of a (zero-terminated) string, and a character c, and removes all instances of the character from the string. Also, write a main program to test your procedure. Your main program should input a string from the user (you can assume that the string will be at most 40 characters, not including the zero byte delimiter), and then prompt for input of a character c. If the character c that the user inputs is the newline character (ascii code 10), your program should terminate. Otherwise, your program should invoke your procedure, output the modified string, and then prompt for input of another character to be removed from the string, continuing in this manner until the input character is the newline character
write a program to count the number of data elements equal (FF)H in a set of data starting at address (0100)H and ended with the value of (00)H.
3. Implement a 32-bit subtraction of two numbers X and Y that are stored in memory as: X = (DS: 503H) MS byte of MS word (DS: 0502H) (DS: 0501H) (DS: 0500H) LS byte of MS byte of LS byte of MS word LS word LS word Y = (DS:0507H) (DS: 0506H) (DS: 0505H) (DS: 0504H) The result of X - Y is to be saved in the place where X is stored in memory.
this is Computer architecture! WRITE THE PROGRAM IN MIPS LANGUAGE! The assignment is to create a MIPS programs that the determines what the ECC code should be for a given number (an 8-bit byte). ECC Hamming codes are explained on pages 420-424 in your text. The codes you create are to work for 8-bit positive numbers as these are simpler to work with than larger numbers. The program is to request the user to enter a byte of data (a positive integer in the range of 0 to 255 in decimal) and then create the 12-bit Hamming code as described in your text (see above). The program is to then output this (with an appropriate label) in hex. Make certain that you have lots of comments in your code as this is in MIPS. Also make the code neat: line up the instruction columns, the register columns, and the comment fields (see page 134 in your text for a nice example). For this assignment, turn in your code, a screenshot showing a working for a test case SHOW THE PROGRAM WORKING PLEASE
in C++ generate a histogramLinks to an external site. of 20,000 randomly generated integer numbers according to a normal distribution with a user-specified mean and standard deviation. Your histogram will include the frequencies of at least 9 data points centering at the mean value: mean +/- x*stdDev, where x is in {0, 1, 2, 3, 4}. For example, given mean=1 and standard deviation of 2, you will calculate the frequency of at least the following values: 1-4*2, 1-3*2, 1-2*2, 1-2, 1, 1+2, 1+2*2, 1+3*2, 1*4*2.
Using C Language In this function, b has the address of a memory buffer that is num_bytes long. The function should repeatedly copy the 16 byte pattern that pattern16 points at into the memory buffer until num_bytes have been written. If num_bytes is not a multple of 16, the final write of the 16 byte pattern should be truncated to finish filling the buffer. void memset16(void *b, int num_bytes, void *pattern16) For example if the 16 bytes that pattern16 points at is 00 11 22 33 44 55 66 77 88 99 aa bb cc dd ee ff, then memset(b, 20, pattern16) should write to the buffer pointed at by p the 20 bytes 00 11 22 33 44 55 66 77 88 99 aa bb cc dd ee ff 00 11 22 33. Use SSE instructions to improve efficiency. Here's pseudocode. x = SSE unaligned load from pattern16while (num_bytes >= 16) SSE unaligned store x to p advance p by 16 bytes decrement num_bytes by 16while (num_bytes > 0) store 1 byte from pattern16 to p advance p by 1 byte advance pattern16 by 1 byte…
int X[900]; int Y[600]; int sum, sum1, sum2, sum3; //parallelism : dividing outer loop in three parts //i = 1 to 300 for(i=1;i<=300;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 301 to 600 for(i=301;i<=600;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } //i = 601 to 900 for(i=601;i<=900;i++) { for(j=1;j<600;j++) { sum1 = X[i] + Y[j]; } } sum = sum1 + sum2 + sum3;} another way to solve the question that send in the pic
Write a Program in C Language.
Write a C program that uses the following: a main() to read two integer values from the user, val1 and val2, and prints the returned value from swap().a swap() that uses call by reference (takes the addresses into pointers) to swap values, and prints their values after the swap "num1 = # and num2 = #". This function returns the largest of the two values. If these are equal, it returns their sum.
switch (c) { case 1: a = 10; break; case 2: a = 20; break; case 3: a = 30; break; default: a = 0; } Translate this piece of C codes into ILOC codes. Variable c and a should be stored in the activation record. Your translated codes start at address 1000 and grow to larger addresses. The address of a variable in the activation record is r_arp[@name], where r_arp is the register storing the activation record address and @name is the macro for the offset of the variable name. You may use labels instead of address number in jump/branch instructions.
1- True or False : Switching time should be high for faster execution. 2-What is the protocol that used to solve the priority inversion problem.

SEE MORE QUESTIONS

Recommended textbooks for you

Database System Concepts

Computer Science

ISBN:

9780078022159

Author:

Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:

McGraw-Hill Education

Starting Out with Python (4th Edition)

Computer Science

ISBN:

9780134444321

Author:

Tony Gaddis

Publisher:

PEARSON

Digital Fundamentals (11th Edition)

Computer Science

ISBN:

9780132737968

Author:

Thomas L. Floyd

Publisher:

PEARSON

Database System Concepts

Computer Science

ISBN:

9780078022159

Author:

Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:

McGraw-Hill Education

Starting Out with Python (4th Edition)

Computer Science

ISBN:

9780134444321

Author:

Tony Gaddis

Publisher:

PEARSON

Digital Fundamentals (11th Edition)

Computer Science

ISBN:

9780132737968

Author:

Thomas L. Floyd

Publisher:

PEARSON

C How to Program (8th Edition)

Computer Science

ISBN:

9780133976892

Author:

Paul J. Deitel, Harvey Deitel

Publisher:

PEARSON

Database Systems: Design, Implementation, & Manag…

Computer Science

ISBN:

9781337627900

Author:

Carlos Coronel, Steven Morris

Publisher:

Cengage Learning

Programmable Logic Controllers

Computer Science

ISBN:

9780073373843

Author:

Frank D. Petruzella

Publisher:

McGraw-Hill Education

SEE MORE TEXTBOOKS