**Problem 3:** Enter the net ionic equation, including phases, for the reaction of \( \text{AgNO}_3(aq) \) and \( \text{KCl}(aq) \). Refer to the solubility rules as needed.**Net Ionic Equation:** \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_**Explanation:** To derive the net ionic equation, begin by writing the balanced molecular equation for the reaction. Then, express the ionic compounds that are soluble in water as ions. Identify and cancel the spectator ions, which do not participate in forming the precipitate.In this reaction, silver nitrate (\( \text{AgNO}_3 \)) and potassium chloride (\( \text{KCl} \)) react to form silver chloride (\( \text{AgCl} \)), a precipitate, and potassium nitrate (\( \text{KNO}_3 \)), which remains in solution.1. **Molecular Equation:** \[ \text{AgNO}_3(aq) + \text{KCl}(aq) \rightarrow \text{AgCl}(s) + \text{KNO}_3(aq) \]2. **Ionic Equation:** \[ \text{Ag}^+(aq) + \text{NO}_3^-(aq) + \text{K}^+(aq) + \text{Cl}^-(aq) \rightarrow \text{AgCl}(s) + \text{K}^+(aq) + \text{NO}_3^-(aq) \]3. **Net Ionic Equation:** \[ \text{Ag}^+(aq) + \text{Cl}^-(aq) \rightarrow \text{AgCl}(s) \]In this net ionic equation, the \( \text{Ag}^+ \) and \( \text{Cl}^- \) ions combine to form solid silver chloride, \( \text{AgCl}(s) \). The \( \text{K}^+ \) and \( \text{NO}_3^- \) ions are spectator ions and are not included in the net ionic equation.

Net ionic equation is that chemical equation which presents the electrolytes in dissociated ionic…

Answered: 3. Enter the net ionic equation,…

3. Enter the net ionic equation, including phases, for the reaction of AgN0;(aq) and KCI (aq). Refer to the solubility rules as needed. net ionic equation:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Please don't provide handwritten solution ....
What is the balanced net ionic equation for this reaction. Pb(NO,),(aq) + 2HCI(aq) PBCI, (s) + 2HN0,(aq) HCl and HNO, are both strong acids.
A 0.8159 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly dissolved in water to make 50 mL of solution. It required 22.07 mL of NaOH to reach the endpoint in the titration. What is the molarity of the NaOH solution? I mg IHE/ 2.022 4 mol 0.81599 Hcl 36.4bg.
An acid-base titration reaches its end point when iõð mlL of 8.2 M HCI Is ådded to 50 mL of NaOH. What is the concentration of the NaOH (M)?
Given the following information: hydrocyanic acid Ka = 4.0E-10 HCN HF hydrofluoric acid Ka = 7.2E-4 (1) Write the net ionic equation for the reaction that occurs when equal volumes of 0.236 M aqueous hydrocyanic acid and sodium fluoride are mixed. It is not necessary to include states such as (aq) or (s). A₂ A² A₂ A² A₂ A² A₂ A² (2) At equilibrium the ✓will be favored. (3) The pH of the resulting solution will be seven.
b) Water "softeners" work via the principle of ion-exchange. The tank of a water softener is filled with a soluble salt such as sodium chloride. As "hard" water passes through the tank, the undesirable ions in hard water (e.g., calcium, magnesium, and iron III) are exchanged for the more desirable "soft" (meaning more soluble) ions like sodium. Explain how swapping the "soft"-water sodium ions for "hard"-water ions would influence the behavior (the cleaning effectiveness) of soaps and detergents.
A 185.0 mL sample of 1.200 M Pb(NO₃)₂ is mixed with 52.50 mL of 1.500 M NaCl, and the PbCl₂ precipitate is filtered from the solution. Then 200.0 mL of 3.000 M NaBr is added to the remaining solution, and the PbBr₂ precipitate is also collected and dried. What is the mass (in grams) of the PbBr₂ precipitate, assuming the yield in each precipitation step is 100%?
d) A 38.5mL sample of 0.875M AgNO, solution is mixed with 51.0mL sample of 0.744M NaCl solution. The AgCl precipitated has a mass of 2.06g. Calculate the limiting reactant, the theoretical yield, and percent yield. AGNO3(aq) + NaClaq) → AGCI6) + NaNO3(aq)