3. [Electrostatic precipitators] A 98% efficient electrostatic precipitator is being designed to treat a gas stream flowing at 5000 m³/min. Calculate both the total plate area and the number of plates required, knowing the following: The effective drift velocity is 6 cm/s; Each plate has a length of 6 m and a height of 10 m; - The ESP contains three sections and each section must have the same number of plates. [Ans: total plate area = 5433.4 m²; number of plates = 48 ]
3. [Electrostatic precipitators] A 98% efficient electrostatic precipitator is being designed to treat a gas stream flowing at 5000 m³/min. Calculate both the total plate area and the number of plates required, knowing the following: The effective drift velocity is 6 cm/s; Each plate has a length of 6 m and a height of 10 m; - The ESP contains three sections and each section must have the same number of plates. [Ans: total plate area = 5433.4 m²; number of plates = 48 ]
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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[Ans: total plate area 5433.4 m2 ; number of plates = 48 ]
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Transcribed Image Text:• The particle removal efficiency is given by:
Ap
exp(-wete)
n=1 - exp
The effective drift velocity (w.) is
proportional to:
• average voltage through the discharge
wires (Vavg)
Corona discharge current (Ic)
We & Vavg. Ic
Since Vavg. Ic = corona discharge
power: w₂x corona power
A major issue with ESPs is the significant
electrical demands for maintaining the
corona.
Design component of the ESP
Number of plate channels
within the ESP (N)
Number of collector sections
along the length of the ESP (NS)
Overall length of the ESP (L.)
Total collection plate area (Ap)
Equation
Na
Ns
=
Qg
uWZ
removal efficiency (-)
Electrostatic Precipitators (ESPs)
Ꭱ Ꮓ
Lp
A₁ = total collection plate area
Qg = volumetric flowrate or waste gas
W₂ = effective drift velocity.
1
Several components of the ESP must be sized, including the plates and housing:
• Number of plate channels within the ESP
• Number of collector sections along the length of the ESP
• Overall length of the precipitator
• Total collection plate area
Ap = 2 Z Lp Ns Na
0.8
0.6
0.4
0.2
0
Note: example graph for academic purposes (not real data)
0
Ap/Qg = 50 s/m
Ap/Qg = 25 s/m
Ap/Qg = 12.5 s/m
0.05
0.1
0.15
effective drift velocity (m/s)
Comments
u = waste gas velocity
W = channel width
Z = plate height.
0.2
13
R = aspect ratio (= effective length /Z)
L₂= length of one plate
Ls = spacing between plate sections
Lo = NsLp + (Ns − 1)Ls + Len + Lex Len= length of entrance section
Lex = length of exit section
Note that the plates have two sides,
hence the factor 2
14
![3. [Electrostatic precipitators] A 98% efficient electrostatic precipitator is being designed to treat a
gas stream flowing at 5000 m³/min. Calculate both the total plate area and the number of plates
required, knowing the following:
- The effective drift velocity is 6 cm/s;
Each plate has a length of 6 m and a height of 10 m;
-
The ESP contains three sections and each section must have the same number of plates.
[Ans: total plate area = 5433.4 m²; number of plates = 48 ]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fde55ad6b-27eb-44c5-bca1-afdb32f2dfc7%2Fe7ec2d5c-3768-4810-8a1d-9fb6750bf5ef%2Faf5kccr_processed.png&w=3840&q=75)
Transcribed Image Text:3. [Electrostatic precipitators] A 98% efficient electrostatic precipitator is being designed to treat a
gas stream flowing at 5000 m³/min. Calculate both the total plate area and the number of plates
required, knowing the following:
- The effective drift velocity is 6 cm/s;
Each plate has a length of 6 m and a height of 10 m;
-
The ESP contains three sections and each section must have the same number of plates.
[Ans: total plate area = 5433.4 m²; number of plates = 48 ]
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