3. Determine the pH of the buffer solution below: 0.25 M NH3 and 0.30 M NH4+ with pka = 4.76

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### Buffer Solution pH Calculation

#### Problem Statement:
Determine the pH of the buffer solution below:

0.25 M \( \text{NH}_3 \) and 0.30 M \( \text{NH}_4^+ \) with \( \text{p}K_a = 4.76 \).

#### Solution:
To determine the pH of this buffer solution, we can use the Henderson-Hasselbalch equation: 

\[
\text{pH} = \text{p}K_a + \log \left( \frac{[\text{Base}]}{[\text{Acid}]} \right)
\]

In this case:
- The base (\(\text{NH}_3\)) concentration is \( 0.25 \, M \).
- The acid (\(\text{NH}_4^+\)) concentration is \( 0.30 \, M \).
- \( \text{p}K_a \) is \( 4.76 \).

Substituting these values into the equation:

\[
\text{pH} = 4.76 + \log \left( \frac{0.25}{0.30} \right)
\]

\[
\text{pH} = 4.76 + \log \left( \frac{5}{6} \right)
\]

\[
\log \left( \frac{5}{6} \right) \approx -0.079
\]

\[
\text{pH} = 4.76 - 0.079
\]

\[
\text{pH} \approx 4.68
\]

Thus, the pH of the buffer solution is approximately 4.68.
Transcribed Image Text:### Buffer Solution pH Calculation #### Problem Statement: Determine the pH of the buffer solution below: 0.25 M \( \text{NH}_3 \) and 0.30 M \( \text{NH}_4^+ \) with \( \text{p}K_a = 4.76 \). #### Solution: To determine the pH of this buffer solution, we can use the Henderson-Hasselbalch equation: \[ \text{pH} = \text{p}K_a + \log \left( \frac{[\text{Base}]}{[\text{Acid}]} \right) \] In this case: - The base (\(\text{NH}_3\)) concentration is \( 0.25 \, M \). - The acid (\(\text{NH}_4^+\)) concentration is \( 0.30 \, M \). - \( \text{p}K_a \) is \( 4.76 \). Substituting these values into the equation: \[ \text{pH} = 4.76 + \log \left( \frac{0.25}{0.30} \right) \] \[ \text{pH} = 4.76 + \log \left( \frac{5}{6} \right) \] \[ \log \left( \frac{5}{6} \right) \approx -0.079 \] \[ \text{pH} = 4.76 - 0.079 \] \[ \text{pH} \approx 4.68 \] Thus, the pH of the buffer solution is approximately 4.68.
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