3. Determine the internal energy of an HCl molecule having one quantum of vibrational excitation (v=1) and three quanta (J=3) of rotational excitation. (v = 2990.9 cm³¹ and B = 10.59 cm ¹)

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3. Determine the internal energy of an HCl molecule having one quantum of vibrational
excitation (v=1) and three quanta (J=3) of rotational excitation. (v = 2990.9 cm³¹ and B =
10.59 cm ¹)
Transcribed Image Text:3. Determine the internal energy of an HCl molecule having one quantum of vibrational excitation (v=1) and three quanta (J=3) of rotational excitation. (v = 2990.9 cm³¹ and B = 10.59 cm ¹)
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Step 1: Introduction


To determine the internal energy of an HCl molecule with one quantum of vibrational excitation (v-1) and three quanta (J-3) of rotational excitation, we can use the following formula for the internal energy of a diatomic molecule:


E = (v + 0.5) * h * v + (J * (J + 1)) * B


Where:


E is the internal energy.

v is the vibrational quantum number (v-1 in this case).

h is Planck's constant (6.626 x 10^-34 J·s)

B is the rotational constant (10.59 cm⁻¹ in this case).

J is the rotational quantum number (J-3 in this case).

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